The abscissa of the ordered pair, that is the x-coordinate, is equal to 1 and the ordinate, the y-coordinate, is equal to -1. In the cartesian plane, this point lies in the fourth (IV) quadrant. The standard position of the angle is that which has one of its side is in the x-axis.
Solve for the hypotenuse of the right triangle formed.
h = sqrt((-1)² + (1)²) = √2
Below items show the calculation for each of the trigonometric functions.
sin θ = opposite/hypotenuse = y/h = (-1)/(√2) = -√2/2
cos θ = adjacent/hypotenuse = x/h = (1)/√2 = √2/2
tan θ = opposite/adjacent = y/x = -1/1 = -1
Answer:
<h2>
<em>h</em><em>(</em><em>x</em><em>)</em><em>=</em><em>9</em><em>x</em><em>-</em><em>1</em><em>3</em></h2>
<em>Sol</em><em>ution</em><em>,</em>
<em>
</em>
<em>hope</em><em> </em><em>this</em><em> </em><em>helps</em><em>.</em><em>.</em><em>.</em>
<em>Good</em><em> </em><em>luck</em><em> on</em><em> your</em><em> assignment</em><em>.</em><em>.</em>
The answer is A. Y=square root of 2x
Answer:
One solution
Step-by-step explanation:
Lets solve it for b
3b= -6a+12
3b= 6a-12
Simplifying
b= -2a+4
b= 2a+4
Both have same slope and intercept hence both lines are going to intersect at one point. So the equations are having one solution.
Answer:
Yes that a good answer...
