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Rasek [7]
3 years ago
12

A line passes through the points -3 -4 and 6 2 what is the Y intercept of this line? -3 -2 2 or 3​

Mathematics
1 answer:
Ymorist [56]3 years ago
8 0

Answer:

y=-2

Step-by-step explanation:

Hello : let  A(-3,-4)    B(6,2)

the slope is :   (YB - YA)/(XB -XA)

(2+4)/(6+3)  = 6/9 = 2/3

an equation is the line is : y = ax+b        a is a slope

y = (2/3)x+b

but this line passes by (6;2)

so : 2 = (2/3)(6)+b

b = -2

the equation is : y = (2/3)x-2

the the Y intercept of this line when : x= 0   so : y = (2/3)(0)-2

y=-2

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Write the equation of the line that passes. Throught the point (-2,1)and (0,8)put your aswer in fully reduce point slope form un
Soloha48 [4]

Answer:

Step-by-step explanation:

first, we need to find the slope

slope = (y2 - y1) / (x2 - x1)

(-2,1)...x1 = -2 and y1 = 1

(0,8)...x2 = 0 and y2 = 8

now sub

slope = (8 - 1) / (0- (-2) = 7/(0 + 2) = 7/2

point slope form : y - y1 = m(x - x1)

using point (-2,1)....x1 = -2 and y1 = 1

slope(m) = 7/2

now sub

y - 1 = 7/2(x - (-2) =

y - 1 = 7/2(x + 2) <==== here is one answer

y - y1 = m(x - x1)

using point (0,8)...x1 = 0 and y1 = 8

slope(m) = 7/2

now sub

y - 8 = 7/2(x - 0) <===== another possible answer

6 0
3 years ago
A meuseum added 18 painting to its collection in may. This is 20% of paintings the meuseum has in April. How many paintings did
Alexus [3.1K]

18 / x = 20 / 100

20x = 1800

x = 90

The museum had 90 paintings in April.

Hope this helps!! :)

5 0
3 years ago
Two distinct planes _ intersect at a pair of lines
maxonik [38]
Sometimes

/20characters
6 0
3 years ago
Find the volume of the figure.
Valentin [98]

11.2 x 11 x 8 is 985.6

so uh- yeah i hope that helped lol

6 0
2 years ago
Given that the mass of an average linebacker at Ursinus College is 250 lbs and the radius of a pea is 0.50 cm, calculate the num
Brilliant_brown [7]

Answer:

1.544*10⁹ Linebackers would be required in order to obtain the same density as an alpha particle

Step-by-step explanation:

Assuming that the pea is spherical ( with radius R= 0.5 cm= 0.005 m), then its volume is

V= 4/3π*R³ = 4/3π*R³ = 4/3*π*(0.005 m)³ = 5.236*10⁻⁷ m³

the mass in that volume would be  m= N*L (L= mass of linebackers=250Lbs= 113.398 Kg)

The density of an alpha particle is  ρa= 3.345*10¹⁷ kg/m³ and the density in the pea ρ will be

ρ= m/V

since both should be equal ρ=ρa , then

ρa= m/V =N*L/V → N =ρa*V/L

replacing values

N =ρa*V/L = 3.345*10¹⁷ kg/m³ * 5.236*10⁻⁷ m³ /113.398 Kg  = 1.544*10⁹ Linebackers

N=1.544*10⁹ Linebackers

7 0
3 years ago
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