Question

A pipe discharges wine into a 1.5-m-diameter tank. Another pipe (15 cm diameter), located near the base of the tank, is used to discharge wine out of the tank. Calculate the volumetric flow rate into the tank if the wine level remains constant at 2.5 m.

Answer 1

Answer:

Volumetric flow rate = $v=0.1232 m^3 /s$

Step-by-step explanation:

The volumetric flow rate v= area x velocity

from the given data we will find out area and velocity first.

Area = A = (π /4) d^2

Diameter = d = 15 cm = 0.15 m

Area = A = $(3.14/4) * 0.15^2\\Area = A =0.0176 m^2$

The velocity  = V = $\sqrt{2gH}$

height of wine in the tank = H = 2.5 m

$Velocity = V = \sqrt{2*9.8*2.5}\\Velocity = V = 7 m/s$

Now calculating the volumetric flow rate

v = A x V

v = 0.0176 x 7

$v=0.1232 m^3 /s$