The cross of a green budgie and a yellow budgie produces offspring that are 12 green, 4 blue, 13 yellow, and 3 albino. what are
the genotypes of the parents?
1 answer:
Genotypes:
blue: yyBb or yyBB
yellow: Yybb or YYbb
albino: yybb
green: YyBb or YYBB or YyBB or YYBb
32 offspring
The cross between the parents need to be like: Yybb x YyBb
that way, if you follow the table down below, 6/16 will be green (it's the same as saying 12/32); 6/16 are yellow (about the same as 13/32); 2 albinos, and 2 blue offspring (2/16 is the same as 4/32 and close to 3/32).
blue: yyBb or yyBB
yellow: Yybb or YYbb
albino: yybb
green: YyBb or YYBB or YyBB or YYBb
32 offspring
The cross between the parents need to be like: Yybb x YyBb
that way, if you follow the table down below, 6/16 will be green (it's the same as saying 12/32); 6/16 are yellow (about the same as 13/32); 2 albinos, and 2 blue offspring (2/16 is the same as 4/32 and close to 3/32).
You might be interested in
Answer:
Please find the expected genotypes and phenotypes of the progenies of each cross below.
Explanation:
In the MN blood-group locus of the gene, alleles LM and LN exhibit codominance i.e one allele is not dominant or recessive to the other, hence, they are both expressed when they occur in a heterozygous state (MN).
Considering the following crosses (find the punnet square attached);
a)LMLM x LMLN - The progeny are LMLM and LMLN in the genotypic ratio 1:1. Phenotypic ratio is Blood type M (1) : blood type MN (1)
b) LNLN x LNLN - The progeny are all LNLN offsprings with a phenotypic and genotypic ratio 4:0. All offsprings will have a blood type N (4)
c) LMLN x LMLN - The progenies are LMLM, LMLN and LNLN in the genotypic ratio 1:2:1 respectively. The phenotypic ratio is Blood type M (1) : L
Blood type MN (2) : Blood type N (1)
d) LMLN x LNLN - The progeny are LMLN and LNLN with genotypic ratio 1:1 and phenotypic ratio blood type MN (1) : blood type N (1)
e) LMLM x LNLN - The progeny are all LMLN offsprings with penotypic ratio blood type MN (4)
