He needs to work 22 hours :)
Answer:
I just need points
Step-by-step explanation:
I just need points
Answer:
c: -7
Step-by-step explanation:
Answer:
Step-by-step explanation:
Recall that
and
for all
. So


For
, we expect both
and
(i.e. the sine and cosine of any angle that lies in the first quadrant must be positive). By definition of absolute value,
if
.
So we have

making H the answer.
C is always true, because the inequality reduces to x > y.