55 = 5 * 11
As any number divisible by 5 must end with 0 & 5
hence possible values of b are 0 & 5
few examples
55 * 20 = 1100
55 * 21 = 1155
55 * 40 = 2200
55 * 41 = 2255
55*60 = 3300
55*61 = 3355
55*80 = 4400
55*81 = 4455
55*100 = 5500
55*180 = 9900
55*181 = 9955
A= 2bh/1-2h idk of I’m right or not
Answer:
944
Step-by-step explanation:
Answer:
![173.21cm^2](https://tex.z-dn.net/?f=173.21cm%5E2)
Step-by-step explanation:
![A=\frac{\sqrt{3} }{4} a^2\\P=3a\\](https://tex.z-dn.net/?f=A%3D%5Cfrac%7B%5Csqrt%7B3%7D%20%7D%7B4%7D%20a%5E2%5C%5CP%3D3a%5C%5C)
Solve for A
![A=\sqrt{3} \frac{P^2}{36} \\=\sqrt{3} *\frac{60^2}{36} \\=173.21cm^2](https://tex.z-dn.net/?f=A%3D%5Csqrt%7B3%7D%20%5Cfrac%7BP%5E2%7D%7B36%7D%20%5C%5C%3D%5Csqrt%7B3%7D%20%2A%5Cfrac%7B60%5E2%7D%7B36%7D%20%5C%5C%3D173.21cm%5E2)
Lets start with the algebraic equation
5x=15
you want to isolate the variable in the equation so you end up with x= ...
x is being multiplied by 5, in order to cancel out the 5 divide the entire equation by 5 (BOTH SIDES OF THE EQUATION)
5x=15
———
5
5x becomes x
15 becomes 3
you are left with x=3