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3 years ago

Which property is this 6y-y + 2y + 10 - 4+2

Mathematics

1 answer:

kicyunya [14]3 years ago

6 0

Find what’s y then multiple and add

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Can someone help its algebra?

aalyn [17]

Answer:

see explanation

Step-by-step explanation:

The perimeter is the sum of the 3 sides of the triangle , that is

3x + 2x + 6 + 6x - 3 ( simplify by collecting like terms )

= 11x + 3

Given the perimeter = 36 units , then

11x + 3 = 36 ( subtract 3 from both sides )

11x = 33 ( divide both sides by 11 )

x = 3

Then

base = 2x + 6 = 2(3) + 6 = 6 + 6 = 12 units

height = 3x = 3(3) = 9 units

hypotenuse = 6x - 3 = 6(3) - 3 = 18 - 3 = 15 units

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2 years ago

Are fractions reversible? why or why not

olga2289 [7]

Answer:

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2 years ago

Read 2 more answers

A student solved this problem by working backward. Jared has some flowers. He has 6 more red flowers than yellow flowers. He has

goldenfox [79]

5 + 7 = 12 silver balloons
12 x 3 = 36 bronze
12 + 36 + 5 = 53

4 0

3 years ago

HELP PLEASE 15 POINTS

vodomira [7]

The answer is c hopefully it helps you

7 0

3 years ago

A firework is launched at the rate of 10 feet per second from a point on the ground 50 feet from an observer. to 2 decimal place

Kazeer [188]

The rate of change of the angle of elevation when the firework is 40 feet above the ground is 0.12 radians/second.

First we will draw a right angle triangle ΔABC, where ∠B = 90°

Lets, assume the height(AB) = h and base(BC)= x

If the angle of elevation, ∠ACB = α, then

tan(α) = $\frac{AB}{BC} = \frac{h}{x}$

Taking inverse trigonometric function, α = tan⁻¹ ( $\frac{h}{x}$ ) .............(1)

As we need to find the rate of change of the angle of elevation, so we will differentiate both sides of equation (1) with respect to time (t) :

$\frac{d\alpha}{dt}=[\frac{1}{1+ \frac{h^2}{x^2}}]*(\frac{1}{x})\frac{dh}{dt}$

Here, the firework is launched from point B at the rate of 10 feet/second and when it is 40 feet above the ground it reaches point A,

that means h = 40 feet and $\frac{dh}{dt}$ = 10 feet/second.

C is the observer's position which is 50 feet away from the point B, so x = 50 feet.

$\frac{d\alpha}{dt}= [\frac{1}{1+ \frac{40^2}{50^2}}] *\frac{1}{50} *10\\ \\ \frac{d\alpha}{dt} = [\frac{1}{1+\frac{16}{25}}] *\frac{1}{5}\\ \\ \frac{d\alpha}{dt} = [\frac{25}{41}] *\frac{1}{5}\\ \\ \frac{d\alpha}{dt}= \frac{5}{41} =0.1219512$

= 0.12 (Rounding up to two decimal places)

So, the rate of change of the angle of elevation is 0.12 radians/second.

5 0

3 years ago