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Leviafan [203]
3 years ago
6

What is −412√+75√ in simplest radical form?

Mathematics
2 answers:
guapka [62]3 years ago
4 0
Ok  
√12 = √4 * √3 = 2√3
√75 = √25*√3 = 5√3

so 4√12 + √75 = 4*2√3 + 5√3  = 13√3  answer
Mnenie [13.5K]3 years ago
3 0
<h3>Answer:  13√3.</h3>

Step-by-step explanation: Given radical expression 4√12 + √75.

Let us simplify each of the radical separately first.

√12 = √(2×2×3) = 2√3

Therefore, 4√12 = 4 × 2√3 = 8√3.

√75 = √(3×5×5) = 5√3

Therefore 4√12 + √75  => 8√3 + 5√3.

Adding like radicals, we get

8√3 + 5√3 = 13√3.

<h3>Therefore, 4√12 + √75 = 13√3.</h3>
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Answer:

Step-by-step explanation:

Given that:

T(x,y) = \dfrac{100}{1+x^2+y^2}

This implies that the level curves of a function(f) of two variables relates with the curves with equation f(x,y) = c

here c is the constant.

c = \dfrac{100}{1+x^2+2y^2} \ \ \--- (1)

By cross multiply

c({1+x^2+2y^2}) = 100

1+x^2+2y^2 = \dfrac{100}{c}

x^2+2y^2 = \dfrac{100}{c} - 1 \ \  -- (2)

From (2); let assume that the values of c > 0 likewise c < 100, then the interval can be expressed as 0 < c <100.

Now,

\dfrac{(x)^2}{\dfrac{100}{c}-1 } + \dfrac{(y)^2}{\dfrac{50}{c}-\dfrac{1}{2} }=1

This is the equation for the  family of the eclipses centred at (0,0) is :

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a^2 = \dfrac{100}{c} -1  \ \ and \ \ b^2 = \dfrac{50}{c}- \dfrac{1}{2}

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The sketch of the level curves can be see in the attached image below.

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3 years ago
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