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Evgen [1.6K]
3 years ago
13

How to do square routs of 8

Mathematics
2 answers:
Hoochie [10]3 years ago
8 0
Multiply the square route of 2 and the route of 4 to get the square route of 8 



I hope this helps and have a wonderful day filled with joy!!
Daniel [21]3 years ago
5 0
Multiply the sqaure route of 2 and the route of 4 to get the square route of 8 


Hope this helps!
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PLEASE HELP SUPER EASY!!!
Effectus [21]

A1. 12 i.e option D

A2. 3n-7 i.e option A

A3. -6n+20 i.e option D

A4. -70 i.e option C

Step-by-step explanation:

aₙ = a₁ + (n - 1) × d  

aₙ = the nᵗʰ term in the sequence

a₁ = the first term in the sequence

d = the common difference between terms

Using the above formula to solve the first part, we have :

  • -8 = a₁ + (2-1) × 5
  • -13 = a₁
  • a₆ = -13 + (6-1) × 5
  • a₆ = 12

For the second part, we have :

  • aₙ = -4 + (n-1)×3
  • aₙ = -4 + 3n -3
  • aₙ = 3n-7

For the third part, we have :

  • a₁=14 ; d=-6
  • aₙ = 14 + (n-1)×(-6)
  • aₙ = -6n + 20

For the fourth part, we have :

  • aₙ = 14 + (15-1)×(-6)
  • aₙ = -70
7 0
3 years ago
Make an equation that would equal to 6, numbers u can use is 4,9,1,5
steposvetlana [31]
Write down : 2, +, 3 + 1
8 0
3 years ago
Read 2 more answers
12x+3y=-9 <br><br>find y- intercept​
ivolga24 [154]

Answer:

3

Step-by-step explanation:

subtract 3y from both sides

add 9 to both sides

3y=12x+9

divide everything by 3

y=4x+3

y-intercept is 3

6 0
3 years ago
Mr Thompson please answer. This is hw that is for mathematics Algebra.
ddd [48]

Answer:

question 6:

x^{2} + 9x + 14 and (x + 2) (x + 7)

question 7:

x^{2} - 7x + 10 and (x - 2)(x - 5)

question 8:

x^{2} - 9x + 20 and (x - 4)(x - 5)

question 9:

(x + 1) (x - 17)

x^{2} - 17x + 1x - 17

x^{2} - 16x - 17

question 10:

(x - 1) (x + 17)

x^{2} + 17x - 1x - 17

x^{2} + 16x - 17

6 0
3 years ago
10.) Which equation below represents the model? A. m - 11 = 43 B. 11m = 43 C. m + 11 = 43 D. m + 43 = 11.) What is the value of
elixir [45]

Answer:

A

Step-by-step explanation:

m - 11 = 43

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3 years ago
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