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4 years ago

Write the decimal as a fraction 0.12

Mathematics

2 answers:

Juli2301 [7.4K]4 years ago

7 0

The answer is 12/100. This is because the 12 is a 100 decimal place.

uysha [10]4 years ago

5 0

12/100 would be the answer but it can be simplified to 3/25

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Five times a number is ten more than three times the number. Find the number

natita [175]

5x = 10 + 3x

5x - 3x = 10

2x = 10

x = 5

To check

5(5) = 10 + 3(5)

25 = 10 + 15

25 = 25

4 0

2 years ago

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What is the lowest term of 44:11

Lorico [155]

Answer:

1/4

Step-by-step explanation:

11/44 =

11/(22 × 11) =

(11 ÷ 11) / ((22 × 11) ÷ 11) =

1/22 =

1/4

6 0

3 years ago

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Two glasses of milk and 3 snack bars have a total of 61 carbohydrates (carbs), and 4 glasses of milk and 2 snack bars have a to

Sloan [31]

Answer:

24 carbohydrates

Step-by-step explanation:

Represent Snack bars with S and Milks with M.

So, we have:

$2M\ and\ 3S\ = 61$

and

$4M\ and\ 2S\ = 70$

Required: Solve for M and S

Convert the given expressions to mathematical expressions:

$2M + 3S = 61$ --- (1)

$4M + 2S = 70$ --- (2)

Multiply the first equation by 2

$2M + 3S = 61$ --------- * 2

$4M + 6S = 122$ --- (3)

Subtract (1) from (3)

$4M - 4M + 6S - 2S = 122 - 70$

$4S = 52$

Solve for S

$S = 52/4$

$S = 13$

Substitute 13 for S in (2)

$4M + 2S = 70$

$4M + 2 * 13 = 70$

$4M + 26 = 70$

Solve for 4M

$4M = 70 - 26$

$4M = 44$

Solve for M

$M = 44/4$

$M = 11$

1 glass of milk and 1 snack bar = S + M

$S + M = 13 + 11$

$S + M = 24$

6 0

3 years ago

Suppose that E and F are two events and that Upper P left parenthesis Upper E and Upper F right parenthesisequals0.1 and Upper P

strojnjashka [21]

Answer:

P(F/E) = 0.5

Step-by-step explanation:

We have the following information:

P(E∩F)=0.1

P(E)=0.2

Additionally, the probability P(A/B) of event A given Event B is calculated as:

P(A/B) = P(A∩B)/P(B)

Now, we want the probability P(F/E), so it is calculated as:

P(F/E) = P(E∩F)/P(E)

Finally, replacing the values we get:

P(F/E) = 0.1 / 0.2

P(F/E) = 0.5

4 0

3 years ago

Solve The Equation By Cramer's Rule:

lord [1]

Thx for the points, have a nice dayyy

5 0

3 years ago

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