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Alex Ar [27]
3 years ago
15

Write the decimal as a fraction 0.12

Mathematics
2 answers:
Juli2301 [7.4K]3 years ago
7 0
The answer is 12/100. This is because the 12 is a 100 decimal place.
uysha [10]3 years ago
5 0
12/100 would be the answer but it can be simplified to 3/25
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Suppose you write a sum of numbers as a product of their GCF and another sum. What is the GCF of the numbers in the other sum? C
vivado [14]

Answer:

1

Step-by-step explanation:

7 0
2 years ago
What is the value of X in the triangle below to the nearest degree? The triangle is not drawn to scale. I selected an answer but
11Alexandr11 [23.1K]

Answer:

x = 25

Step-by-step explanation:

To find the value of x we use the formula:

tan x° = opposite side /adjacent side

Opposite Side = 8

Adjacent Side = 17

tan x° = 8/17

tan x° = 0.4705882352941

Tan^{-1} of 0.4705882352941

x° = 25

4 0
3 years ago
The results of a survey of 43 students and the foreign language they are studying are shown in the two-way frequency table.
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Since 5 out of 43 people take chinese, it's 5/43 which is the same as 0.116 which means 11,6%

I hope this was helpful! Tell me if it's unclear!
4 0
3 years ago
Janelle tips 20% for service at restaurants. When she left a restraurant, she saw the total she paid for her meal was $14.82.
wariber [46]
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8 0
3 years ago
Read 2 more answers
Lesson: 1.08Given this function: f(x) = 4 cos(TTX) + 1Find the following and be sure to show work for period, maximum, and minim
Ber [7]

The given function is

f(x)=4\cos \text{(}\pi x)+1

The general form of the cosine function is

y=a\cos (bx+c)+d

a is the amplitude

2pi/b is the period

c is the phase shift

d is the vertical shift

By comparing the two functions

a = 4

b = pi

c = 0

d = 1

Then its period is

\begin{gathered} \text{Period}=\frac{2\pi}{\pi} \\ \text{Period}=2 \end{gathered}

The equation of the midline is

y_{ml}=\frac{y_{\max }+y_{\min }}{2}

Since the maximum is at the greatest value of cos, which is 1, then

\begin{gathered} y_{\max }=4(1)+1 \\ y_{\max }=5 \end{gathered}

Since the minimum is at the smallest value of cos, which is -1, then

\begin{gathered} y_{\min }=4(-1)+1 \\ y_{\min }=-4+1 \\ y_{\min }=-3 \end{gathered}

Then substitute them in the equation of the midline

\begin{gathered} y_{ml}=\frac{5+(-3)}{2} \\ y_{ml}=\frac{2}{2} \\ y_{ml}=1 \end{gathered}

The answers are:

Period = 2

Equation of the midline is y = 1

Maximum = 5

Minimum = -3

3 0
10 months ago
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