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navik [9.2K]
3 years ago
6

What is 8 divided by 827

Mathematics
1 answer:
Dima020 [189]3 years ago
6 0
The answe is 103.375, because when you divide 827 by 8, you get the answer of 103.375. To be sure, you may also type it in a calculator, and you'll noticed you'll get the same answer.
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The sum of two numbers is 8, and their difference is 22. What are the numbers?
BabaBlast [244]

Answer:

i will say 15 and -7

Step-by-step explanation:

15+-7=8 and 15--7=22

15+-7 so take the negative and take out that mush of the big number

15-7=8

15--7= the subtracting beside a negative makes it changes to positive and addition so 15+7=22

7 0
4 years ago
What is the product of 9 3/7 x 10/3 =
erica [24]

Answer: 31 3/7

Step-by-step explanation: Simply just multiply 66 by 10 = 660 and then divide 660 by 21 and you get 31 3/7!

4 0
2 years ago
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HELP!!!! PLEASE!!!!! NEED ANSWER ASAP!! I DON'T UNDERSTAND!! the answer is not always increasing
USPshnik [31]
Maybe the answer is D
7 0
3 years ago
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Arithmetic??????????????????
wel

good lesson and good day ^-^

7 0
3 years ago
Part A: The Sun produces 3.9 ⋅ 1033 ergs of radiant energy per second. How many ergs of radiant energy does the Sun produce in 3
Nuetrik [128]

5914 1404 393

Answer:

  A) 1.3×10^37 ergs

  B) 1.435×10^3 mm

Step-by-step explanation:

A) The amount of energy will be the product of the energy rate and time:

  (3.9×10^33 ergs/s)×(3.25×10^3 s) =12.675×10^(33+3) ergs

  = 1.2675×10^(1+36) ergs

  = 1.2675×10^37 ergs ≈ 1.3×10^37 ergs

The mantissa of the result is the product 3.9×3.25, adjusted to have one digit left of the decimal point. The exponent of the result is the sum of the exponents of the factors, adjusted by 1 to match the adjustment in the mantissa.

The final value should be rounded to 2 significant figures, reflecting the precision of the sun's energy production.

__

B) A millimeter is a small fraction of an inch. 10^-3 mm is a small fraction of the width of a human hair, so 1.435×10^-3 mm is not a reasonable estimate of the distance between railroad tracks.

On the other hand, 1.435×10^3 mm is 1.435 m, almost 56.5 inches. This is a much more reasonable measurement of the distance between railroad rails.

  1.435×10^3 mm is more reasonable

8 0
3 years ago
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