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ratelena [41]
3 years ago
7

If it is -14 degrees celsius how much warmer does it need to get before ice will begin to melt?

Mathematics
2 answers:
Cloud [144]3 years ago
8 0

Por favor, no elimines esto, necesito puntos. Pero creo que serían

veinte, no estoy muy seguro ...

Serggg [28]3 years ago
6 0

Answer:

15 degrees celsius

Step-by-step explanation:

15 degrees is needed to get to 1 degree celsius

if 0 degrees celsius is when it freezes then 1 should be where it begins to melt

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Ilia_Sergeevich [38]

a very fast way to do it:

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3 years ago
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timurjin [86]

Answer:

2.  12 2/9

Step-by-step explanation:

Because of the choices, I assume the three addends are mixed numerals:

3 4/7 + 4 2/9 + 4 3/7 =

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= 11 + 7/7 + 2/9

= 11 + 1 + 2/9

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Answer: 2.  12 2/9

3 0
3 years ago
Find the area of the shaded polygon.
Zarrin [17]

Answer:

<h2>A = 64 sq. un</h2>

Step-by-step explanation:

This is a trapezium.

The formula od an area of a trapezium:

A = 1/2(a + b) · h

We have:

a = 10, b = 6, h = 8

substitute:

A = 1/2 · (10 + 6) · 8 = 1/2 · 16 · 8 = 8 · 8 = 64

3 0
3 years ago
The hypotenuse of right triangle is 116 meters long. The difference between the other two sides is 4 meters. Find the missing si
Scilla [17]

Answer:

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Step-by-step explanation:

The hypotenuse is the longest side of the right angle triangle. Let x represent the length of the longer side of the triangle. The difference between the other two sides is 4 meters. It means that the length of the shorter side is x - 4

Applying Pythagoras theorem which is expressed as

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Therefore,

116² = x² + (x - 4)²

13456 = x² + x² - 4x - 4x + 16

2x² - 8x + 16 - 13456 = 0

2x² - 8x - 13440 = 0

Dividing through by 2, it becomes

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x² + 80x - 84x - 6720 = 0

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5 0
3 years ago
circle q is centered at the origin with radius r point p(xy)lies on circle q make conjecture how can you find an equation relati
babunello [35]

Answer:

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Step-by-step explanation:

We know that the center-radius form of the circle equation is in the format (x – h)2 + (y – k)2 = r2, with the center being at the point (h, k) and the radius being "r".

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x^{2}+y^{2}=r^{2}

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