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lana [24]
4 years ago
9

Solve for n. −5/6n=40 What is the answer A.−56 B.−48 C.48 D.56

Mathematics
2 answers:
stiv31 [10]4 years ago
7 0
It should be -48. Multiply 40 by the reciprocal and simplify.
Zinaida [17]4 years ago
7 0
Its -48 did the test and it is this
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PLEASE WILL MARK BRANLIEST AND IS WORTH 20POINTS!!!!!
svlad2 [7]

Answer:

(3,-2)

Step-by-step explanation:

Part A:

1) <em>Isolate x in x - y = 5</em>

x = y + 5

2) <em>Substitute that x into 4x+y=10</em>

4(y + 5) + y = 10

4y + 20 + y = 10

5y = 10-20

5y = -10

y = -2

3) Use y to solve for x:

x = -2 + 5

x = 3

Part B:

<em>Verify using results from Part A</em>

3 - (-2) = 5

4(3) + (-2) = 12 - 2 = 10

Part C:

<em>Just graph the equations and see where they intersect, which is exactly (3,-2). We got that in Part A and B</em>

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4 years ago
Please Help Very much confuse and I have to turn this in before this evening
Oksana_A [137]

Answer:

b

Step-by-step explanation:

3 0
3 years ago
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Given f(x) and g(x) = f(x) + k, use the graph to determine the value of k.
Evgesh-ka [11]

Answer:

  k = 3

Step-by-step explanation:

The value of k is the amount by which the function f(x) is translated upward to give the function g(x). We can compare y-intercepts to see that the y-intercept of g(x) is 5 -2 = 3 units more than the y-intercept of f(x). This means ...

  g(x) = f(x) +3

Comparing to ...

  g(x) = f(x) +k

we see that k = 3.

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2 years ago
Hs Geometry <br> Solve for a
asambeis [7]

Answer:

the answer is A ........._________---------

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3 years ago
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Writing Equations of Parallel Lines
Nookie1986 [14]

Answer:

The slope of the parallel line to the given line is -\frac{1}{4}

The equation of the parallel line to the given line and passes through the given point is y + 4 =  -\frac{1}{4} (x + 2)

The y-intercept of the parallel line to the given line and passes through the given point is  -\frac{9}{2}

Step-by-step explanation:

  • The rule of the slope of the line that passes through points (x1, y1) and (x2, y2) is m = \frac{y2-y1}{x2-x1}
  • The point-slope form of the linear equation is y - y1 = m(x - x1), where m is the slope and (x1, y1) is a point on the line
  • The slope-intercept form of the linear equation is y = m x + b, where m is the slope and b is the y-intercept
  • Parallel lines have the same slopes and different y-intercepts

In the given figure

∵ The given line passes through points (2, 6) and (-6, 8)

∴ x1 = 2 and y1 = 6

∴ x2 = -6 and y2 = 8

→ Substitute them in the rule of the slope above to find it

∵ m = \frac{8-6}{-6-2} = \frac{2}{-8} = -\frac{1}{4}

∴ The slope of the given line is -\frac{1}{4}  

∵ Parallel lines have the same slopes

∴ The slope of the parallel line to the given line is -\frac{1}{4}

∵ The parallel line passes through the point (-2, -4)

∴ x1 = -2 and y1 = -4

∵ m = -\frac{1}{4}

→ Substitute them in the point-slope form above

∵ y - (-4) = -\frac{1}{4} (x - (-2))

∴ y + 4 =  -\frac{1}{4} (x + 2)

∴ The equation of the parallel line to the given line and passes through

   the given point is y + 4 =  -\frac{1}{4} (x + 2)

∵ m = -\frac{1}{4}

→ Substitute it in the slope-intercept form above

∴ y =  -\frac{1}{4} x + b

→ To find b substitute x by -2 and y by -4 (coordinates the given point)

∵ -4 = -\frac{1}{4}(-2) + b

∴ -4 = \frac{1}{2} + b

→ Subtract  \frac{1}{2}  from both sides

∴ -\frac{9}{2} = b

∵ b is the y-intercept

∴ The y-intercept of the parallel line to the given line and passes

   through the given point is  -\frac{9}{2}

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3 years ago
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