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3 years ago

5

How do you solve this with order of operation?

1 answer:

Wittaler [7]3 years ago

7 0

The order order operations is "PEMDAS" Which means you would solve anything with in P: Parenthesis first, anything with E: exponents second, Do M:multiplication/D:division next, and leave A:addition/S:subtraction for last.

I hope this helps, but I need to know the equation or expression to the problem to walk you through it.

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2 years ago

Order each set of numbers from least to greatest.<br><br><br> PLZ HELP ASAP

Wittaler [7]

Answer:

<h3><u>7. Ans ;</u></h3>

$\frac{41}{3} < 14 < \sqrt{200}$

<h3><u>8</u><u>.</u><u> </u><u>Ans</u><u> </u><u>;</u></h3>

<u> $0.6 < \frac{2}{3} < \sqrt{ \frac{9}{16} }$ </u>

Step-by-step explanation:

<h3><u>7. Ans ;</u></h3>

$\sqrt{200} = 10 \sqrt{2} = 14.1 \\ 14 = 14 \\ \frac{41}{3} = 13.6$

So ;

$\frac{41}{3} < 14 < \sqrt{200} \\ 13.6 < 14 < 14.1$

<h3><u>8. Ans ;</u></h3>

$\frac{2}{3} = 0.66 \\ \sqrt{ \frac{9}{16} } = \frac{3}{4} = 0.75 \\ 0.6 = 0.6$

So ;

$0.6 < \frac{2}{3} < \sqrt{ \frac{9}{16} } \\ 0.6 < 0.66 < 0.75$

I hope I helped you^_^

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2 years ago