Answer:
NaNO₃ > C₆H₁₂O₆ > C₁₂H₂₂O₁₁
Explanation:
Boiling-point elevation is defined as the phenomenon where boiling point of a liquid will be higher when another compound is added, meaning that a solution has a higher boiling point than a pure solvent. The formula is:
ΔT = k×m×i
Where k is ebulloscopic constant of the solvent, m is molality of solution in moles of solute per kg of solution and i is Van't Hoff factor (1 in glucose and sucrose and 2 in sodium nitrate).
Molality is proportional to moles of solute. As the solutions have the same concentration in mass, <em>the lowest molar mass of solute, the highest boiling point elevation</em>.
Molar mass of glucose is 180,2 g/mol; sucrose 342,3 g/mol and sodium nitrate 85 g/mol.
As sodium nitrate has the lowest molar mass and a Van't Hoff factor of 2, its solution will have the highest boiling point, then will be glucose (In order to its molar mass), and the lowest boiling point will be sucrose. Thus, in order of decreasing boiling point:
<em>NaNO₃ > C₆H₁₂O₆ > C₁₂H₂₂O₁₁</em>
<em></em>
I hope it helps!
Answer:
Ok, so the process here is to convert the mass of H2 (hydrogen gas) to moles by dividing the mass by the molar mass of H2. Once you have the moles then you have to multiply by the STP (standard temperature and pressure) molar volume which should be 22.4.
Molar mass of H2 = (1.01)x2 = 2.02g/mol
19.3/2.02 = 9.55 moles
Now just multiply the moles by the molar volume
9.55 moles x 22.4 = 213.92 Litres of H2 are in 19.3g of H2
Answer:
See explanation
Explanation:
We can describe electrons using four sets of quantum numbers;
principal quantum number (n)
orbital quantum number (l)
magnetic quantum number (ml)
spin quantum number (ms)
Since no two electrons in an atom can have the same value for all four quantum numbers according to Pauli exclusion theory, for the orbitals given one possible value for each quantum number is shown below;
For 1s-
n = 1, l= 0, ml = 0, ms= 1/2
For 2s-
n= 2, l =0, ml=0, ms=1/2
For 1s and 2s orbitals, there is only one possible value for ml which is zero.
Answer:
The net ionic equation is as follows:
HCN(aq) + OH-(aq) ----> H20(l) + CN-(aq)
Explanation:
The reaction between Hydrocyanic acid, HCN, and sodium hydroxide is a neutralization reaction between a weak acid and a strong base.
Hydrocyanic acid being a weak acid ionizes only slightly, while sodium hydroxide being a strong base ionizes completely. The equation for the reaction is given below:
A. HCN(aq) + NaOH-(aq) ----> NaCN(aq) + H2O(l)
Since Hydrocyanic acid is written in the aqueous form as it ionizes only slightly and the ionic equation is given below:
HCN(aq) + Na+(aq)+OH-(aq) ----> Na+(aq)+CN-(aq) + H2O(l)
Na+ being a spectator ion is removed from the net ionic equation given below:
HCN(aq) + OH-(aq) ----> H20(l) + CN-(aq)
Answer:
10.5L
Explanation:
The volume in this question can be calculated by using the formula for gas law equation as follows:
PV = nRT
Where;
P = pressure (atm)
V = volume (litres)
n = number of moles (mol)
R = gas law constant (0.0821 Latm/molK)
T = temperature (K)
According to the provided information in this question:
P = 6.18 atm
V = ?
n = 2.35 moles
R = 0.0821 Latm/molK
T = 63°C = 63 + 273 = 336K
Using PV = nRT
V = nRT/P
V = 2.35 × 0.0821 × 336/ 6.18
V = 64.83/6.18
V = 10.49
V = 10.5L