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attashe74 [19]
3 years ago
6

~lever

Chemistry
1 answer:
aleksandr82 [10.1K]3 years ago
3 0
Block and tackle d is the best answer
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How does a catalyst appear in a chemical equation
Alinara [238K]
<span> A </span>catalyst<span> will </span>appear<span> in the steps of a </span>reaction<span> mechanism, but it will not </span>appear<span> in the overall </span><span>chemical reaction</span>
4 0
4 years ago
(Based on q = -sm∆T)
vekshin1

Answer:

Sn < Brass ≈ Zn <   Al  

Step-by-step explanation:

                      Sn   < Brass  ≈   Zn   <   Al

C/J·°C⁻¹g⁻¹: .0.246 <  0.418 ≈ 0.419 < 0.734

3 0
4 years ago
When a solution of lead nitrate is added to a solution of lithium chloride, a precipitate forms.
Simora [160]

Answer:

c

Explanation:

I just want to get to the app

8 0
3 years ago
Thermal Chemistry [11A.S, 11B.S. 11C.R, 11D.S]:Question 2
777dan777 [17]

Answer:

25 degrees

Explanation:

Q= mc^T

84= (2.0)(4.18)^T

84= 8.36^T

Divide each side by 8.36

^T= 10 degrees

15+ 10= 25

Final temp= 25

5 0
3 years ago
At high pressures, real gases do not behave ideally. calculate the pressure exerted by 25.0 g h2 at 20.0°c in a 1.00 l container
Gemiola [76]
Van der Waals equation is as follows:
(P + a(n/V)²) * (V -nb) = n RT
Moles of H₂ is calculated by dividing 25 g by 2 (molecular weight of H₂) = 12.5 moles
Values of a and b are:
a = 0.02444 atm L² / mol
b = 0.0266 L / mol
(P + 0.02444 (12.5/1)²) * (1 -(12.5 *0.0266)) = 12.5 * 0.0821 * 293 K
If we solve this equation we get pressure of 412.29 atm

With ideal gas equation we get:
P V = n R T
P = n * R * T / V = (12.5 * 0.0821 * 293 / 1) = 300.69 atm
3 0
4 years ago
Read 2 more answers
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