Answer:
The answer to the question is
The rate constant for the reaction is 1.056×10⁻³ M/s
Explanation:
To solve the question, e note that
For a zero order reaction, the rate law is given by
[A] = -k×t + [A]₀
This can be represented by the linear equation y = mx + c
Such that y = [A], m which is the gradient is = -k, and the intercept c = [A]₀
Therefore the rate constant k which is the gradient is given by
Gradient = ![\frac{[A]_{2} - [A]_{1} }{t_{2} - t_{1} }](https://tex.z-dn.net/?f=%5Cfrac%7B%5BA%5D_%7B2%7D%20-%20%5BA%5D_%7B1%7D%20%20%7D%7Bt_%7B2%7D%20-%20t_%7B1%7D%20%20%7D)
where [A]₁ = 8.10×10⁻² M and [A]₂ = 1.80×10⁻³ M
= 
= -0.001056 M/s = -1.056×10⁻³ M/s
Threfore k = 1.056×10⁻³ M/s
The following is the introduction to a special e-publication called Determining the Age of the Earth (click the link to see a table of contents). Published earlier this year, the collection draws articles from the archives of Scientific American. In the collection, this introduction appears with the title, “Stumbling Toward an Understanding of Geologic Timescales.”
Answer:
A. LST
Explanation:
• 1st Law: The path of each planet around the Sun is an ellipse with the Sun at one focus.
• 2nd Law: The line from the Sun to any planet sweeps out equal areas of space in equal time intervals.
• 3rd Law: The square of the orbital period of a planet is directly proportional to the cube of the average distance
