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3 years ago

9

Jill is doing a science experiment. After she mixes some baking soda into some

1 answer:

sertanlavr [38]3 years ago

8 0

I think it's C. Please mark brainliest

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Oceanic crust is

Ratling [72]

Answer:

It is thinner than the continental crust.

Explanation:

4 0

3 years ago

Read 2 more answers

Which has a higher melting point and why? LiF or Rbl?

ExtremeBDS [4]

Explanation:

To get a better understanding of the answer,let's take use of Fajan's rule which says that no bond is neither purely covalent or purely ionic.

For ionic compounds MP and BP are higher than covalent compounds. So in order to find the one with higher MP,it's enough to find the most ionic compound among the given options.

In LiF,LiCl,LiBr and LiI,The cation is same and anion only differs.According to Fajans rule Smaller anion and larger cation favours ionic bonding and vice versa. Since Fluoride is the smallest anion,LiF is the most ionic compound and hence it is the one with highest MP from the options.Hope it helps

7 0

3 years ago

Convert 45 joules to heat calories

skad [1K]

Answer:

45 joules to calories= 10 (10.755258) calories

3 0

4 years ago

Calculate the energy released in each of the following fusion reactions. Give your answers in MeV. (a) 2H + 3H → 4He + n 17.54 C

Vikentia [17]

Answer:

a) E = 17.55 MeV

b) E = 18.99 MeV

c) E = 3.29 MeV

d) You can use the methods applied for the other parts to solve this, the equation is not properly written

e) E = 4.075 MeV

Explanation:

Energy Released, $E = \triangle M * 931.5$

$\triangle M = \sum M_{product} - \sum M_{reactant}$

Mass of 1H, $M_{H} = 1.007823$

Mass of 2H, $M_{2H} = 2.0141u$

Mass of 3H, $M_{3H} = 3.016 u$

Mass of Helium, $M_{4He} = 4.002602u$

Mass of Beryllium, $M_{7Be} = 7.01693 u$

Mass of neutron, $M_{n} = 1.008664 u$

a) $2H + 3H \rightarrow 4He + n$

$\triangle M = (4M_{He} + M_{n} ) - (2M_{H} + 3 M_{H} )\\\triangle M = ( 4.0026 + 1.008664) - (2.0141 + 3.016 )\\\triangle M = -0.01884u$

Energy released,

$E = -0.01884 * 931.5\\E = -17.55 Mev$

Energy released = 17.55 MeV

b) $4He + 4He \rightarrow 7Be + n$

$\triangle M = (M_{7Be} + M_{n} ) - (M_{4He} + M_{4He} )\\\triangle M = ( 7.01693 + 1.008664) - (4.002602 + 4.002602 )\\\triangle M = 0.02039 u$

Energy released,

$E = 0.02039 * 931.5\\E = 18.99 Mev$

c) $2H + 2H \rightarrow 3 He$ + n

$\triangle M = (M_{3He} + M_{n} ) - (M_{2H} + M_{2H} )\\\triangle M = ( 3.016 + 1.008664) - (2.0141 + 2.0141 )\\\triangle M = -0.003536 u$

Energy released,

$E = -0.003536 * 931.5\\E = -3.29 Mev$

E = 3.29 MeV(Energy is released)

d) You can use the methods applied for the other parts to solve this, the equation is not properly written

e) $2H + 2H \rightarrow 3H + 1H$

$\triangle M = (M_{3H} + M_{1H} ) - (M_{2H} + M_{2H} )\\\triangle M = ( 3.016 + 1.007825) - (2.0141 + 2.0141 )\\\triangle M = -0.00435 u$

$E = -0.00435 * 931.5\\E =-4.075 Mev$

E = 4.075 MeV ( Energy is released)

5 0

3 years ago

The acid dissociation constant, Ka, of HNO3 is 4.0 x104. What does the ka

Shtirlitz [24]

Answer:

i thing its b

Explanation:

3 0

3 years ago