Your answer would be 135.

This is because angles on a straight line add up to 180°, and so we need to subtract 45 from 180, which gives us 135.

I hope this helps!

6 0

3 years ago

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A population of rabbits oscillates 19 above and below average during the year, hitting the lowest value in january. the average

Helen [10]

Answer:

$p(t)=650+\frac{160}{12}t+19sin(\omega t)$

Step-by-step explanation:

The initial value of the population is 650

Each year the population increases 160

The population oscillates 19 above and below.

Due to this information you can assume that the function is:

$p(t)=650+\frac{160}{12}t+19sin(\omega t)$

where for t=0 p(t)=650

where t=12 160/12 (12) = 160

you can assume that the sinusoidal function has a period of one month. Thus, the population oscillates several times in one year with an amplitu of the oscillation of 19. The, w is:

$\omega (1)=2\pi\\\\\omega=2\pi$

4 0

3 years ago

The measurts of the angles of a triangle are shown in the figure below. Solve for x.<br> 33°<br> A

andrew11 [14]

Answer:

Step-by-step explanation:

4 0

3 years ago

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