9514 1404 393
Answer:
7. d. l = 6.48 cm, w = 6.48 cm
8. d. square
Step-by-step explanation:
For a given area, the perimeter can always be shortened by reducing the length of the long side and increasing the length of the short side. When you get to the point where you can't do that, then you have the minimum perimeter. You will reach that point when the sides are the same length: the rectangle is a square.
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7. In light of the above, the best dimensions are √42 ≈ 6.48 cm for length and width.
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8. In light of the above, the shape is a square.
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The attached graph shows the length of one side (x) and the associated perimeter. The other side is 42/x, which will also be 6.48.
Answer:
600,000
Step-by-step explanation:
When rounding to the nearest 100,000 if it's X50,000 you round up 1 for the X, if it's X49,999 or less you keep the X as is.
229,275 rounding to the hundred thousand would be 200,000
115,368 would be 100,000
344,633 would be 300,000
so 200,000+100,000+300,000 = 600,000
Answer:
4g-124= -104, g-12= -7
Step-by-step explanation:
g=5
4g-124= ? g-12
4(5)-124 5-12
4(5)= 20 5-12= -7
20 - 124= -104
So remember the acronym "SOH CAH TOA"
- Sin = Opposite/Hypotenuse
- Cos = Adjacent/Hypotenuse
- Tan = Opposite/Adjacent
- Opposite = Side that doesn't touch the angle
- Adjacent = Side that touches the angle
- Hypotenuse = Side that is across from the right angle
<h3>A.</h3>
So we see that side a doesn't touch angle
, hence making it the opposite side. And we see that side b is across from the right angle, making it the hypotenuse. <u>Using this info,
</u>
<h3>B.</h3>
So we already know from part A that side b is the hypotenuse. And also since side c touches the angle, it is the adjacent.<u> Using this info,
</u>
<h3>C.</h3>
Next, it has been established that side c is the adjacent and side a is the opposite side. <u>Using this info,
</u>
The function given is a composite function. Let's work from the outside in:

First step:
![\frac{d}{dx}[y]= \frac{d}{dx}[ln(sinh(2x))]](https://tex.z-dn.net/?f=%20%5Cfrac%7Bd%7D%7Bdx%7D%5By%5D%3D%20%5Cfrac%7Bd%7D%7Bdx%7D%5Bln%28sinh%282x%29%29%5D)
Now, let's work it out:
![\frac{dy}{dx} = \frac{1}{sinh(2x) } * \frac{d}{dx}[sinh(2x)]](https://tex.z-dn.net/?f=%5Cfrac%7Bdy%7D%7Bdx%7D%20%3D%20%5Cfrac%7B1%7D%7Bsinh%282x%29%20%7D%20%2A%20%20%20%5Cfrac%7Bd%7D%7Bdx%7D%5Bsinh%282x%29%5D)
Next step:
![\frac{dy}{dx} = \frac{1}{sinh(2x) } * cosh(2x) * \frac{d}{dx}[2x]](https://tex.z-dn.net/?f=%5Cfrac%7Bdy%7D%7Bdx%7D%20%3D%20%5Cfrac%7B1%7D%7Bsinh%282x%29%20%7D%20%2A%20cosh%282x%29%20%2A%20%20%5Cfrac%7Bd%7D%7Bdx%7D%5B2x%5D%20)
Next step:

Simplify:

Simplify further:

Remember that:

So,
your final answer is:
So, your answer is
C. Hope I could help you!