Hello :
f(x) = sin²(x) +cos(x)
the dirivate is : f'(x) = 2sin(x) cos(x) -sin(x) because :
( sin²(x) )' = 2sin(x) cos(x) and (cos(x))' = - sin(x)
f'(x) = 0 : sin(x) (2cos(x) - 1) = 0
sin(x) = 0 : x = k <span>π k in Z
</span>2cos(x) - 1 =0 : 2cos(x) =1
cos(x) = 1/2 = cos( π /3)
x = π /3 +2k π or x = - π /3 +2k π
in intervall : <span> <span>[0
, 2π] :
k=0 : x= 0 f(0) = 1 ( </span></span>minimum<span>)
</span>k=1 : x = π f(π) = -1 (<span>minimum)
x= </span> π /3 f ( π /3 ) = 1.25 ( <span>maximum)</span>
Ok so what you need to do is first find the area of the circle using π r^2. So π12^2 or π144= 452.389342117 This is the area of the whole circle. To find the area of the sector you have to multiply the total area by 172/360 or 0.47777777777 This will get you 216.141574567 round as necessary but your answer is <span>216.141574567units^2</span>
When solving a system by graphing you need to see where the lines intersect.
Below is a picture of these lines graphed. The green line is y = x +4 and the blue line is y = 4x - 1
The red dot represents the intersection is about (1, 5)
The original point is: (1.667, 5.667)
Hope this helped!
Mean=34 Mode=none Median=32 Range=26
That is, only real numbers can be used in the domain, and only real numbers can be in the range. There are two main reasons why domains are restricted. You cannot divide by 0 . You cannot take the square (or other even) root of a negative number, as the result will not be a real number.
