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vaieri [72.5K]
3 years ago
9

X^2+12=40 what number must you add to complete the square?

Mathematics
1 answer:
posledela3 years ago
4 0

Answer:

Step-by-step explanation:

1) If you really meant X^2+12=40, then this simplifies to x^2 = 28, and therefore x = ±√28, or x = ±2√7.

2) If you meant X^2+12x=40:

a) Take half of the coefficient of x:  that would be (1/2)(12), or 6.  

b) Square this result, obtaining:  6² = 36

c) Add this 36 to x^2 + 12x + 40, and then subtract it:  We get:  

x² + 12x + 36 - 36 = 40, or x² + 12x + 36 = 76

We have to add 36, as indicated above, to "complete the square."

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positive integer

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3 years ago
Cos (90-theta) • cosec90-theta) =tano. How?​
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Answer:

<u>______________________________________________________</u>

<u>TRIGONOMETRY IDENTITIES TO BE USED IN THE QUESTION :-</u>

For any right angled triangle with one angle α ,

  • \cos (90 - \alpha  ) = \sin \alpha  or  \sin(90 - \alpha ) = \cos\alpha
  • cosec \: (90 - \alpha  ) = \sec\alpha   or  \sec(90 - \alpha ) = cosec\:\alpha

<u>SOME GENERAL TRIGNOMETRIC FORMULAS :-</u>

  • <u></u>\sin \alpha = \frac{1}{cosec \: \alpha }  or  cosec \: \alpha  = \frac{1}{\sin \alpha }
  • <u></u>\cos \alpha = \frac{1}{\sec \alpha }  or  \sec \alpha = \frac{1}{\cos \alpha }

<u>______________________________________________________</u>

Now , lets come to the question.

In a right angled triangle , let one angle be α (in place of theta) .

So , lets solve L.H.S.

\cos (90 - \alpha ) \times cosec(90 - \alpha )

=> sin\alpha  \times \sec\alpha

=> \sin\alpha  \times \frac{1}{\cos\alpha }

=> \frac{\sin\alpha }{\cos\alpha }

=> \tan\alpha = R.H.S.

∴ L.H.S. = R.H.S. (Proved)

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