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SIZIF [17.4K]
3 years ago
12

XY bisects RS at point M. If RM = 6, find the length of RS.

Mathematics
1 answer:
IrinaK [193]3 years ago
5 0

Answer: RS = 6

Step-by-step explanation: Not 100% sure but that's what I think the answer is.

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If f left parenthesis x right parenthesis equals x squared minus 3 x plus 5 , then f left parenthesis 4 right parenthesis equals
lord [1]

Answer:

f(4) = 9

Step-by-step explanation:

f left parenthesis x right parenthesis equals x squared minus 3 x plus 5

f(x) = x² - 3x + 5

f left parenthesis 4 right parenthesis equals

f(4) =

f(x) = x² - 3x + 5

When x = 4

f(4) = 4² - 3(4) + 5

= 16 - 12 + 5

= 9

f(4) = 9

6 0
2 years ago
In the triangle pictured, let A, B, C be the angles at the three vertices, and let a,b,c be the sides opposite those angles. Acc
Troyanec [42]

Answer:

Step-by-step explanation:

(a)

Consider the following:

A=\frac{\pi}{4}=45°\\\\B=\frac{\pi}{3}=60°

Use sine rule,

\frac{b}{a}=\frac{\sinB}{\sin A}
\\\\=\frac{\sin{\frac{\pi}{3}}
}{\sin{\frac{\pi}{4}}}\\\\=\frac{[\frac{\sqrt{3}}{2}]}{\frac{1}{\sqrt{2}}}\\\\=\frac{\sqrt{2}}{2}\times \frac{\sqrt{2}}{1}=\sqrt{\frac{3}{2}}

Again consider,

\frac{b}{a}=\frac{\sin{B}}{\sin{A}}
\\\\\sin{B}=\frac{b}{a}\times \sin{A}\\\\\sin{B}=\sqrt{\frac{3}{2}}\sin {A}\\\\B=\sin^{-1}[\sqrt{\frac{3}{2}}\sin{A}]

Thus, the angle B is function of A is, B=\sin^{-1}[\sqrt{\frac{3}{2}}\sin{A}]

Now find \frac{dB}{dA}

Differentiate implicitly the function \sin{B}=\sqrt{\frac{3}{2}}\sin{A} with respect to A to get,

\cos {B}.\frac{dB}{dA}=\sqrt{\frac{3}{2}}\cos A\\\\\frac{dB}{dA}=\sqrt{\frac{3}{2}}.\frac{\cos A}{\cos B}

b)

When A=\frac{\pi}{4},B=\frac{\pi}{3}, the value of \frac{dB}{dA} is,

\frac{dB}{dA}=\sqrt{\frac{3}{2}}.\frac{\cos {\frac{\pi}{4}}}{\cos {\frac{\pi}{3}}}\\\\=\sqrt{\frac{3}{2}}.\frac{\frac{1}{\sqrt{2}}}{\frac{1}{2}}\\\\=\sqrt{3}

c)

In general, the linear approximation at x= a is,

f(x)=f'(x).(x-a)+f(a)

Here the function f(A)=B=\sin^{-1}[\sqrt{\frac{3}{2}}\sin{A}]

At A=\frac{\pi}{4}

f(\frac{\pi}{4})=B=\sin^{-1}[\sqrt{\frac{3}{2}}\sin{\frac{\pi}{4}}]\\\\=\sin^{-1}[\sqrt{\frac{3}{2}}.\frac{1}{\sqrt{2}}]\\\\\=\sin^{-1}(\frac{\sqrt{2}}{2})\\\\=\frac{\pi}{3}

And,

f'(A)=\frac{dB}{dA}=\sqrt{3} from part b

Therefore, the linear approximation at A=\frac{\pi}{4} is,

f(x)=f'(A).(x-A)+f(A)\\\\=f'(\frac{\pi}{4}).(x-\frac{\pi}{4})+f(\frac{\pi}{4})\\\\=\sqrt{3}.[x-\frac{\pi}{4}]+\frac{\pi}{3}

d)

Use part (c), when A=46°, B is approximately,

B=f(46°)=\sqrt{3}[46°-\frac{\pi}{4}]+\frac{\pi}{3}\\\\=\sqrt{3}(1°)+\frac{\pi}{3}\\\\=61.732°

8 0
3 years ago
I NEED HELP SOMEONE PLZZZ HELP ME PLZZZZ
Lina20 [59]

Answer:

3

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
The weight of football players is normally distributed with a mean of 200 pounds and a standard deviation of 25 pounds.Refer to
Dafna11 [192]

Given that

the weight of football players is distributed with a mean of 200 pounds and a standard deviation of 25 pounds.

And we need to find What is the minimum weight of the middle 95% of the players?

Explanation -

Using the Empirical Rule, 95% of the distribution will fall within 2 times of the standard deviation from the mean.

Two standard deviations = 2 x 25 pounds = 50 pounds

So the minimum weight = 200 pounds - 50 pounds = 150 pounds

Hence the final answer is 150 pounds.

3 0
1 year ago
The triangles below are similar. Triangle Y X Z. Side Y X is 6 centimeters, X Z is 7 centimeters, and Z Y is 3 centimeters. Tria
zavuch27 [327]

Answer:

  (c)  Triangle Z Y X is similar to triangle C B A

Step-by-step explanation:

Triangles are similar when corresponding sides have the same ratio. Corresponding sides will have corresponding end point vertices. The similarity statement lists corresponding vertices in the same order.

__

<h3>corresponding sides</h3>

The side lengths, smallest to largest, for the two triangles are ...

  • 3 cm -- ZY
  • 6 cm -- YX
  • 7 cm -- XZ

And for the other triangle, ...

  • 6 cm -- BC
  • 12 cm -- AB
  • 14 cm -- AC
<h3>corresponding vertices</h3>

The points joining the each side to the next one longer, in order for the two triangles, are ...

  Y, X, Z  and  B, A, C

The vertices corresponding to ZYX in the same order are CBA.

  triangle ZYX is similar to triangle CBA

3 0
2 years ago
Read 2 more answers
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