Question

What are the zeros of the function?

Answer 1

Answer:

B. -3

C. 0

E. 4​

Step-by-step explanation:

g (x)=x^3-x^2-12x

Set this equal to zero

0=x^3-x^2-12x

Factor out an x

0=x(x^2-x-12)

Factor inside the parentheses.

What two numbers multiply to -12 and add to -1

-4*3 = -12

-4+3 = -1

0=x(x-4)(x+3)

Using the zero product property

x=0  x-4=0  x+3=0

x=0  x=4   x=-3