What are the zeros of the function?

Mathematics

1 answer:

Gwar [14]3 years ago

5 0

Answer:

B. -3

C. 0

E. 4

Step-by-step explanation:

g (x)=x^3-x^2-12x

Set this equal to zero

0=x^3-x^2-12x

Factor out an x

0=x(x^2-x-12)

Factor inside the parentheses.

What two numbers multiply to -12 and add to -1

-4*3 = -12

-4+3 = -1

0=x(x-4)(x+3)

Using the zero product property

x=0 x-4=0 x+3=0

x=0 x=4 x=-3

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