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4 years ago

What are the zeros of the function?

Mathematics

1 answer:

Gwar [14]4 years ago

5 0

Answer:

B. -3

C. 0

E. 4

Step-by-step explanation:

g (x)=x^3-x^2-12x

Set this equal to zero

0=x^3-x^2-12x

Factor out an x

0=x(x^2-x-12)

Factor inside the parentheses.

What two numbers multiply to -12 and add to -1

-4*3 = -12

-4+3 = -1

0=x(x-4)(x+3)

Using the zero product property

x=0 x-4=0 x+3=0

x=0 x=4 x=-3

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3 years ago

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A person's height is 5-ft 3-in. Their shadow has a length of 3-ft 6-in. If a nearby tree has a shadow of length 10-ft 4-in, what

Alchen [17]

Answer: The height of tree = 15 ft. 6 inches

Step-by-step explanation:

Given: A person's height is 5-ft 3-in = [5 x (12 )+3 ] inches [ 1 ft= 12 inches]

= 63 inches

Their shadow has a length of 3-ft 6-in = [3 x 12+6] inches

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If a nearby tree has a shadow of length 10-ft 4-in = [10 x 12+4] inches

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At the same time,

$\dfrac{\text{Height of tree}}{\text{Height of person}}=\dfrac{\text{Length person's shadow}}{\text{Length of tree's shadow}}\\\\\dfrac{\text{Height of tree}}{63}=\dfrac{124}{42}\\\\\Rightarrow\ \text{Height of tree}=\dfrac{124}{42}\times63=186\ inches\\\\=\dfrac{186}{12}= 15.5 ft\ or\ 15 ft.\ 6\ inches.$

Hence, the height of tree = 15 ft. 6 inches

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3 years ago

Find the domain of the function

krok68 [10]

Answer:

Domain should be Df = {x>-1}

Step-by-step explanation:

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3 years ago

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Plz with steps .. it's very hard can anyone plz

liubo4ka [24]

Answer:

Step-by-step explanation:

$\displaystyle\ \lim_{n \to a} \dfrac{\sqrt{2x}-\sqrt{3x-a} }{\sqrt{x}-\sqrt{a}} =\frac{0}{0} \\\\we\ can \ use\ Hospital's\ Rule\\\\\\f(x)=\sqrt{2x}-\sqrt{3x-a} \qquad f'(x)=\dfrac{2}{2*\sqrt{2x}} -\dfrac{3}{2*\sqrt{3x-a}} \\\\g(x)=\sqrt{x} -\sqrt{a} \qquad g'(x)=\dfrac{1}{2\sqrt{x}} \\\\\\\displaystyle\ \lim_{n \to a} \dfrac{\sqrt{2x}-\sqrt{3x-a} }{\sqrt{x}-\sqrt{a}} =\lim_{n \to a} \dfrac{\dfrac{2}{2*\sqrt{2x}} -\dfrac{3}{2*\sqrt{3x-a}} }{\dfrac{1}{2\sqrt{x}} }\\\\$

$\displaystyle \lim_{n \to a} \dfrac{2\sqrt{x} }{\sqrt{2x}} -\dfrac{3*\sqrt{x} }{\sqrt{3x-a}} =\lim_{n \to a} \dfrac{2 }{\sqrt{2}} -\dfrac{3*\sqrt{x} }{\sqrt{3x-a}}\\\\\\=\dfrac{2}{\sqrt{2}} -\dfrac{3*\sqrt{a} }{\sqrt{2a}}\\\\\\=\dfrac{2}{\sqrt{2}} -\dfrac{3}{\sqrt{2}}\\\\\\=-\ \dfrac{1}{\sqrt{2}}\\\\$

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3 years ago

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Elena-2011 [213]

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3 years ago