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posledela
3 years ago
14

What are the zeros of the function?

Mathematics
1 answer:
Gwar [14]3 years ago
5 0

Answer:

B. -3

C. 0

E. 4​

Step-by-step explanation:

g (x)=x^3-x^2-12x

Set this equal to zero

0=x^3-x^2-12x

Factor out an x

0=x(x^2-x-12)

Factor inside the parentheses.

What two numbers multiply to -12 and add to -1

-4*3 = -12

-4+3 = -1

0=x(x-4)(x+3)

Using the zero product property

x=0  x-4=0  x+3=0

x=0  x=4   x=-3

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kramer
The answer is d, hope this helps
8 0
2 years ago
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Quinn has $31,700 in a savings
Masteriza [31]

Answer:

she will earn $6,657 in interest in 3 years

6 0
2 years ago
(1 point) A random sample of 600 movie goers in Flagstaff found 252 movie goers who had bought popcorn on their last visit. Find
garik1379 [7]

<u>Answer-</u>

A 95% confidence interval for the true percent of movie goers is 36.41% to 44.25%

<u>Solution-</u>

Given,

n = 600 (sample size)

x = 252 (number of people who bought)

Confidence interval = 95%, so z = 1.96

We know that,

\mu = M\pm Z(SE)

where,

M = sample mean

Z  = Z statistic determined by confidence level

SE = standard error of mean

Calculating the values,

M=\frac{x}{n} =\frac{242}{600} =0.4033

Z=1.96 from the tables

SE=\sqrt{\frac{M\times (1-M)}{n}}

\Rightarrow SE=\sqrt{\frac{0.4033\times (1-0.4033)}{600}}=0.02

Putting all the values in the formula,

\mu = M\pm Z(SE)

\mu = 0.4033\pm 1.96(0.02)

=0.4033\pm 0.0392

=0.4425, 0.3641

= 44.25\%,36.41\%

5 0
3 years ago
The following is the recipe to make one dozen muffins: 1 cups flour; 2 cups sugar; 2 tsps. Baking powder; 1 egg; 1 cup Crisco; 1
ivolga24 [154]

1.5 cups of flower, 3 cups sugar, 3 tbsp. baking powder, 1.5 eggs, 1.5 cups of Crisco, 1.5 cups of skim milk (hopefully not skin milk), and 1.5 cups of blueberries. Because 18 is 12 x 1.5 you just multiply all the given numbers by 1.5.

4 0
3 years ago
100 points!!! Please full out all of these ASAP!!! Please show work!!!
Alex

Answer:

look below

Step-by-step explanation:

y = 2 (x + 3)^2 - 2

Geometric figure:  parabola

Alternate forms:

y = 2 (x + 2) (x + 4)

y = 2 (x^2 + 6 x + 8)

-2 x^2 - 12 x + y - 16 = 0

Expanded form:

y = 2 x^2 + 12 x + 16

Roots:

x = -4

x = -2

<u>Properties as a real function: </u>

Domain - R (all real numbers)

Range - {y element R : y>=-2}

Partial derivatives:

d/dx(2 (x + 3)^2 - 2) = 4 (x + 3)

d/dy(2 (x + 3)^2 - 2) = 0

Implicit derivatives:

(dx(y))/(dy) = 1/(12 + 4 x)

(dy(x))/(dx) = 4 (3 + x)

Global minimum:

min{2 (x + 3)^2 - 2} = -2 at x = -3

3 0
3 years ago
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