We can find the diameter of the circle by replacing some values in the formula for circumference. The formula for find the circumference is pi * d, where pi could equal 3.14 or 22/7 and d is the diameter. After dividing pi from both sides (I used 3.14), we have the total of about 21.01, which would be our diameter. We add 4 more feet into it, resulting in 25.01 feet, and we just multiply that by $0.45 to get the total price.
We get around $11.25 as our total price.
Answer:
Cornor should divide the total length of the road on which there is traffic by the length of each of the cars
Step-by-step explanation:
The best calculation he can use is to divide the total length of the road on which we have the traffic by the length of each of the cars
Mathematically, the best way to go about this is to convert the miles to feet then divide by the length of each of the cars
Mathematically 1 mile = 5280 feet
so 5.5 miles will be = 5280 * 5.5 = 29,040 feet
It is this length we shall now divide by 12.5 ft
And that is 29,040/12.5 = 2,323.2
Which is approximately 2,323 cars
Answer:
a= 22.5
b= 37.5
Step-by-step explanation:
<u>In</u><u> </u><u>△</u><u>BCD</u><u>:</u>
Applying Pythagoras' Theorem,
a² +30²= b²
a² +900= b² -----(1)
<u>In</u><u> </u><u>△</u><u>ABC</u><u>:</u>
Applying Pythagoras' Theorem,
b² +50²= (40 +a)² -----(2)
Substitute (1) into (2):
a² +900 +50²= 40² +2(40)(a) +a²<em> </em><em> </em><em> </em><em> </em><em> </em><em>(</em><em>expand</em><em> </em><em>bracket</em><em>)</em>
a² +900 +2500= 1600 +80a +a²
a² +3400= a² +80a +1600 <em>(</em><em>simplify</em><em>)</em>
a² +3400 -a² -80a -1600= 0 <em>(</em><em>bring</em><em> </em><em>everything</em><em> </em><em>to</em><em> </em><em>1</em><em> </em><em>side</em><em>)</em>
-80a +1800= 0
80a= 1800 <em>(</em><em>+</em><em>8</em><em>0</em><em> </em><em>on</em><em> </em><em>both</em><em> </em><em>sides</em><em>)</em>
a= 1800 ÷80
a= 22.5
Subst. a= 22.5 into (1):
22.5² +900= b²
b²= 506.25 +900
b²= 1406.25
b= √1406.25 <em>(</em><em>square</em><em> </em><em>root</em><em> </em><em>both</em><em> </em><em>sides</em><em>)</em>
b= 37.5 <em>(</em><em>reject</em><em> </em><em>negative</em><em> </em><em>value</em><em> </em><em>since</em><em> </em><em>b</em><em> </em><em>is</em><em> </em><em>a</em><em> </em><em>length</em><em>)</em>
☆(a +b)²= a² +2ab +b²
<h3>
Answer: Choice C) Construct a tangent from an external point</h3>
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Explanation:
The idea is that you have some circle and a point outside the circle. This point is labeled M. The center of the circle is point O. A perpendicular bisector is constructed to segment OM, after which a compass is used to draw the arc marking to form point G. Line MG is perpendicular to the radius segment OG. Therefore, line MG is tangent to the circle and it goes through point M.
(2x)^4 = 16x^4 is the continued product
