Answer:
The 95% confidence interval for the population variance is (8.80, 32.45).
Step-by-step explanation:
The (1 - <em>α</em>)% confidence interval for the population variance is given as follows:

It is provided that:
<em>n</em> = 20
<em>s</em> = 3.9
Confidence level = 95%
⇒ <em>α</em> = 0.05
Compute the critical values of Chi-square:

*Use a Chi-square table.
Compute the 95% confidence interval for the population variance as follows:


Thus, the 95% confidence interval for the population variance is (8.80, 32.45).
52/8 = 6
6*8 = 48
52-48 = 4
So 52 = 6*8+4
The quotient is 6, the remainder is 4.
Answer:
x + 3 is the factor of given expression !!!
Step-by-step explanation:
here's the solution in attachment.
9514 1404 393
Answer:
- 0 ≤ m ≤ 7
- 0.4541 cm/month; average rate of growth over last 4 months of study
Step-by-step explanation:
<u>Part A</u>:
The study was concluded after 7 months. The fish cannot be expected to maintain exponential growth for any significant period beyond the observation period. A reasonable domain is ...
0 ≤ m ≤ 7
__
<u>Part B</u>:
The y-intercept is the value when m=0. It is the length of the fish at the start of the study.
__
<u>Part C</u>:
The average rate of change on the interval [3, 7] is given by ...
(f(7) -f(3))/(7 -3) = (4(1.08^7) -4(1.08^3))/4 = 1.08^3·(1.08^4 -1)
≈ 0.4541 cm/month
This is the average growth rate of the fish in cm per month over the period from 3 months to 7 months.