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S_A_V [24]
4 years ago
9

"to improve cardiovascular fitness, _____ workout sessions per week are optimal"

Biology
1 answer:
kkurt [141]4 years ago
6 0
<span>"to improve cardiovascular fitness, 3-5 workout sessions per week are optimal". <span>Cardiovascular wellness is the capacity of the heart, platelets and lungs to supply oxygen-rich blood to the working muscle tissues and the capacity of the muscles to utilize oxygen to create vitality for development.</span></span>
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In addition to water, what would most likely be found in a plant central vacuole?
cricket20 [7]
Your answer would most likely be chlorophyll. :)

6 0
3 years ago
In which process are glucose and oxygen the reactants?
Kipish [7]

Answer:

Cellular Respiration

Explanation:

Respiration = Glucose + Oxygen -> Water + Carbon Dioxide

7 0
3 years ago
As the human population increases, which problem is technology least likely to be able to solve?
Alenkinab [10]
I would be C) 
plz give me the brainliest
6 0
3 years ago
Read 2 more answers
When an object is in motion, it possesses what type of energy?
posledela

When an object is in motion, it possesses kinetic energy.

Option b is the only correct answer

<h3>What is kinetic energy?</h3>

Kinetic energy is the energy a body has or possess due to its relative motion.

Some few examples of kinetic energy are as follows:

  • Running
  • Walking
  • Cycling
  • Car movement
  • Aeroplane flying

Learn more about kinetic energy:

brainly.com/question/8101588

8 0
2 years ago
Alkaptoneuria is a recessive genetic disorder found among North American populations at a frequency of about 1 in 500,000 births
Dafna11 [192]

Answer:

The correct answer is - 1/41,493

Explanation:

Let assume the frequency of the two possible same allele genotype (dominant and recessive) in an inbred population is p and q. Then the frequency of heterozygotes (H) is denoted as:

2pq + 2pqF.  ( where F is the inbreeding coefficient).

The frequency of the two different hoozygotes in inbred population can be calculated as:

p2 + pqF and q2 + pqF. (Where p and q are the allele frequency of the dominant and recessive phenotype.

Given: Frequency of Alkaptonuria (q 2) = 1:500, 000

=> q = 1/707

p = 706/707 ( Approx values)

solution:

Inbreeding coefficient (F) = 1/64

Therefore,

Frequency of Alkaptonuria in second cousins= q 2 + pqF

= 1/500, 000 + (706/707 x 1/707) x (1/64)

= 1/500, 000 + 1/45, 248

= 1/41,493 (approx)

5 0
3 years ago
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