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3 years ago

Solve this equation: 4y + 228 = 352. A. y = 145 B. y = 31 C. y = 3 D. y = – 31

1 answer:

6 0

We'll want to isolate y, so first well subtract 228 from each side
4y+228 minus 228= 4y
352 minus =124
The equation is now 4y=124
Next we'll have to divide each side by 4 that way we'll have y completely alone
4y/4 =y
124/4 =31
Now the equation is y=31
So the correct answer is B. y=31

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Use the fundamental identities and appropriate algebraic operations to simplify the following expression. (18 +tan x) (18-tan x)

andrezito [222]

Answer:

a) $\left(18+\tan \left(x\right)\right)\left(18-\tan \left(x\right)\right)+\sec ^2\left(x\right)=325$

b) The lowest point of $y=\cos \left(x\right)$ , $0\leq x\leq 2\pi$ is when x = $\pi$

Step-by-step explanation:

a) To simplify the expression $\left(18+\tan \left(x\right)\right)\left(18-\tan \left(x\right)\right)+\sec ^2\left(x\right)$ you must:

Apply Difference of Two Squares Formula: $\left(a+b\right)\left(a-b\right)=a^2-b^2$

$a=18,\:b=\tan \left(x\right)$

$\left(18+\tan \left(x\right)\right)\left(18-\tan \left(x\right)\right)=18^2-\tan ^2\left(x\right)=324-\tan ^2\left(x\right)$

$324-\tan ^2\left(x\right)+\sec ^2\left(x\right)$

Apply the Pythagorean Identity $1+\tan ^2\left(x\right)=\sec ^2\left(x\right)$

From the Pythagorean Identity, we know that $1=-\tan ^2\left(x\right)+\sec ^2\left(x\right)$

Therefore,

$324[-\tan ^2\left(x\right)+\sec ^2\left(x\right))]\\324[+1]\\325$

b) According with the below graph, the lowest point of $y=\cos \left(x\right)$ , $0\leq x\leq 2\pi$ is when x = $\pi$

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3 years ago

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ira [324]

Answer:

A is 1/2

B is 2

C is -2

Step-by-step explanation:

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3 years ago

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3 years ago

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Answer:

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shusha [124]

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Step-by-step explanation:

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