All categories

3 years ago

What is the 8th row of Pascal’s triangle?

Mathematics

1 answer:

JulijaS [17]3 years ago

4 0

Answer:

1 7 21 35 35 21 7 1

Step-by-step explanation:

Tbh I just searched it up who memorizes this stuff?

You might be interested in

Suppose you are interested in testing whether the mean income of women in the General Social

zheka24 [161]

Answer:

Options???

Step-by-step explanation:

4 0

2 years ago

WILL MARK BRAINLIEST IF CORRECT!

ziro4ka [17]

Answer:

Answer → Student A was right.

${ \tt{ \sqrt[3]{1944} = \sqrt[3]{(72 \times 27)} }} \\ \\ = { \tt{ \sqrt[3]{72} \times \sqrt[3]{27} }} \\ \\ = { \tt{ \sqrt[3]{72} \times 3}} \\ \\ = { \underline{ \tt{ \: 3 \sqrt[3]{72} } \: }}$

8 0

2 years ago

Read 2 more answers

A school has 300 students.If the ratio of boys to girls is 31 to 44, how many more girls are there in the school?

garri49 [273]

Answer:

there would be 52 more girls I think

Step-by-step explanation:

let x = multiplier then

31x =number of boys

44x = number of girls

Boys + girls = 300

44x + 31x =300

75x = 300

x = 300/75

x = 4 is the multiplier

therefore:

44*4 = 176 girls

31*4 = 124 boys

dif = 52 more girls than boys

hope this helped :)

5 0

2 years ago

The perimeter of a triangle is 27. Each side of the triangle has length 2x-3. What is the value of x?

Bezzdna [24]

Answer:

x=6

Step-by-step explanation:

To find the perimeter of the triangle you need to add up all the sides, so if all the sides are 2x-3 the equation will look like this;

2x-3+2x-3+2x-3=27

which when combining like terms will leave it to be;

6x-9=27

Than move all the factors besides x over to the right side;

6x-9+9=27+9

6x = 36

6x/6 = 36/6

x = 6

so your answer will be x=6

8 0

2 years ago

Factorize the following algebraic expression:

Hoochie [10]

X^2+16-38=0
find what 2 numbers multiply to get -38 and add to get 16
find factors of 38
2 times 19
there is no way to use common factor so use quadratic formula which is
x= $\frac{ -b+\sqrt{b^2-4ac} }{2a}$ or x= $\frac{ -b-\sqrt{b^2-4ac} }{2a}$

ax^2+bx+c=0 subsitte
a=1
b=16
c=-38
subsitute
$\frac{ -16+\sqrt{16^2-4(1)(-38)} }{2(1)}$ = $\frac{ -16+\sqrt{256+152} }{2}$ = $\frac{ -16+\sqrt{408} }{2}$ = $\frac{ -16+2\sqrt{102} }{2}$ = $-8+\sqrt{102}$
so the answers for x are $-8+\sqrt{102}$ and $-8-\sqrt{102}$ which are aprox -2.099504938362 and +18.099504938362
so it would be
(x-[-8+√102])(x+[8+√102])=0

6 0

2 years ago