Segment drawn on scale having end points O (0,0) and A
is a line segment.
O A= ![\sqrt{[\frac{3}{4} -0]^{2} +[\frac{9}{10} -0]^{2}\\\\](https://tex.z-dn.net/?f=%5Csqrt%7B%5B%5Cfrac%7B3%7D%7B4%7D%20-0%5D%5E%7B2%7D%20%2B%5B%5Cfrac%7B9%7D%7B10%7D%20-0%5D%5E%7B2%7D%5C%5C%5C%5C)
O A = 
= 
= 
Now , the same segment actual structure having end points O'(0,0) and B (30,36) is also a line segment.
O'B= 
= 
= 
= 2√549
[Cancelling √549 from numerator and denominator]
So, Actual length = 40 × Length on scale
Answer:
10
Step-by-step explanation:
For an odd number of values, the median is the middle value when you write the values in ascending order.
5, 7, 9, 10, 16, 17, 20
The median is 10.
Step-by-step explanation:
So you add one over the other
3x-2y=7
-3x+5y=5
=
3y=12
Then you divide 3 from both sides
(3y)/3=12/3
y=4
Then you substitute the y=4 in to the equation of your choice
3x-2(4)=7
3x-8=7
3x-8=7
+8 +8
3x=15
x=5
Answer:
Down below
Step-by-step explanation:
Hope this helps!
Answer:
Hello :
y = 2x² - x -6
y = 2 ( x² - 1/2 x - 3)
y = 2 (x² -1/2 x + 1/16 -1/16 -3)
y = 2 (( x - 1/4 )² - 49/16)..... the quadratic formula
y = 0 : ( x - 1/4 )² - 49/16 = 0
( x - 1/4 )² - (7/4)² = 0
( x -1/4-7/4)( x -1/4+7/4)=0
(x -2)(x + 3/2) = 0
x - 2 = 0 or x + 3/2 =0
x = 2 or x = - 3/2