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3 years ago

An automobile’s velocity starting from a complete stop is v(t) = 140t/ 5t+3 where v is measured in feet per second.

Mathematics

2 answers:

Gemiola [76]3 years ago

8 0

Answer: 10 to 20 seconds

Step-by-step explanation:

you have to measure it in feet per measurement

777dan777 [17]3 years ago

4 0

Answer:

velocity increases with time

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Can someone please calculate the length ?

masya89 [10]

<h3>Answer: 11/20</h3>

=====================================================

Work Shown:

x = unknown horizontal length

1/5 = 0.2

Perimeter = 2*(width + length)

P = 2*(0.2 + x)

P = 0.4 + 2x

Set this equal to the given perimeter of 1 & 1/2 = 1.5 and solve for x

0.4 + 2x = 1.5

2x = 1.5-0.4

2x = 1.1

x = (1.1)/2

x = 0.55

x = 55/100

x = (5*11)/(5*20)

x = 11/20

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3 years ago

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Step-by-step explanation:

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3 years ago

If x^2=y^2+z^2 what does x equal?

Zepler [3.9K]

Answer:

$\displaystyle x = \sqrt{y^2 + z^2}$

General Formulas and Concepts:

Pre-Algebra

Equality Property

Algebra i

Terms/Coefficients

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle x^2 = y^2 + z^2$

Step 2: Solve for x

[Equality Property] Square root both sides: $\displaystyle x = \sqrt{y^2 + z^2}$

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3 years ago

Which measure of center and measure of spread would best describe a data set that is bell-shaped and

yarga [219]

C:median and interquartile range

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3 years ago

Leanne is picking out some movies to rent, and she is primarily interested in children's movies and comedies. She has narrowed d

N76 [4]

Answer:

If she wants at least one comedy, there are 1484 different combinations.

Step-by-step explanation:

The order in which she wants to pick the movies is not important. So, we use the combinations formula to solve this question.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question:

She wants combinations of 3 movies, with at least one comedy. The easiest way to find this is finding the total number of combinations of 3 movies, from the set of 25(18 children's and 7 comedies), and subtract by the total number without comedies(which is 3 from a set of 25). So

Total:

3 from a set of 25.

$C_{25,3} = \frac{25!}{3!(25-3)!} = 2300$

Without comedies:

3 from a set of 18.

$C_{18,3} = \frac{18!}{3!(18-3)!} = 816$

At least one comedy:

$2300 - 816 = 1484$

If she wants at least one comedy, there are 1484 different combinations.

8 0

3 years ago