Answer: 2 ÷ 44 ≈ x x
x is 22
Step-by-step explanation:
Sorry, but I have no idea what your "<span>eaqkesbnnn" means.
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If you were supposed to add 0.16 and 0.45, the correct answer would be 0.61.
For
![ax^2+bx+c=0](https://tex.z-dn.net/?f=ax%5E2%2Bbx%2Bc%3D0)
the discriminant is
![b^2-4ac](https://tex.z-dn.net/?f=b%5E2-4ac)
there are 3 basic cases of what happens for different discriminants
1. if the discriminant is less than 0, then there are no real zeroes
2. if the discriminant is 0, then it has 1 zero
3. if the discriminant is greater than 0, it has 2 zeroes
so given
![0=3x^2-7x+4](https://tex.z-dn.net/?f=0%3D3x%5E2-7x%2B4)
a=3,b=-7,c=4
thus the discriminant is
![(-7)^2-4(3)(4)=49-48=1](https://tex.z-dn.net/?f=%28-7%29%5E2-4%283%29%284%29%3D49-48%3D1)
the discriminant is 1. 1 is positive, thus the equation has 2 zeroes because the discriminant is greater than 0
the answer is the equation has two zeroes because the discriminant is greater than 0
Answer:
I thi k its 164÷2 and then thats y but im honestly not sure