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3 years ago

What reasons justify a solution to a rational equation?

Mathematics

1 answer:

Licemer1 [7]3 years ago

4 0

Answer:

A rational equation is an equation containing at least one fraction whose numerator and denominator are polynomials, ... These fractions may be on one or both sides of the equation. A common way to solve these equations is to reduce the fractions to a common denominator and then solve the equality of the numerators.

Step-by-step explanation:

<h3>Hope it works out !!!!</h3>

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Find the volume of this cylinder 9cm 20cm give answer to 1 decimal place

mojhsa [17]

Answer:

the answer is 5,087 or 5,086.8

7 0

3 years ago

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If α and β are the zeroes of the polynomial 6y 2 − 7y + 2, find a quadratic polynomial whose zeroes are 1 α and 1 β .

ollegr [7]

Answer:

$2y^2-7y+6=0$

Step-by-step explanation:

We are given that $\alpha$ and $\beta$ are the zeroes of the polynomial $6y^2-7y+2$

$y^2-\frac{7}{6}y+\frac{1}{3}$

We have to find a quadratic polynomial whose zeroes are $1/\alpha$ and $1/\beta$ .

General quadratic equation

$x^2-(sum\;of\;zeroes)x+ product\;of\;zeroes$

We get

$\alpha+\beta=\frac{7}{6}$

$\alpha \beta=\frac{1}{3}$

$\frac{1}{\alpha}+\frac{1}{\beta}=\frac{\alpha+\beta}{\alpha \beta}$

$\frac{1}{\alpha}+\frac{1}{\beta}=\frac{7/6}{1/3}$

$\frac{1}{\alpha}+\frac{1}{\beta}=\frac{7}{6}\times 3=7/2$

$\frac{1}{\alpha}\times \frac{1}{\beta}=\frac{1}{\alpha \beta}$

$\frac{1}{\alpha}\times \frac{1}{\beta}=\frac{1}{1/3}=3$

Substitute the values

$y^2-(7/2)y+3=0$

$2y^2-7y+6=0$

Hence, the quadratic polynomial whose zeroes are $1/\alpha$ and $1/\beta$ is given by

$2y^2-7y+6=0$

4 0

3 years ago

Please help me i am stuck

kogti [31]

The answer to that is B it’s 60

3 0

3 years ago

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A manpaid rs 510 as income tax when it was 5 paisa per rupee what was his income?

Goshia [24]

The income of the man in discuss as in the task content is; rs 10,200.

<h3>What is the income of the man?</h3>

Since, it follows that 100 paisas make one rupee. This insinuates that the income tax rate which corresponds to 5 paisa per rupee is; 5%.

Hence, the amount earned by the man in discuss can be evaluated as follows;

(5/100) × Income = 510

Hence, Income = 510/0.05 = rs 10,200.