Answer:
The graph in the attached figure
Step-by-step explanation:
we have
----> inequality A
The solution of the inequality A is the shaded area below the solid line
The y-intercept of the solid line is -4
The x-intercept of the solid line is -1
The slope of the solid line is negative
----> inequality B
The solution of the inequality B is the shaded area above the solid line 
The y-intercept of the solid line is 2
The x-intercept of the solid line is -2
The slope of the solid line is positive
The solution of the system of inequalities is the shaded area between the two solids line
see the attached figure
Let's start with triangle RST. This is a 30-60-90 triangle, which means it has the relationship x - x sqrt(3) - 2x.
If RS is 2 sqrt(3), then ST must be 2 and RT must be 4.
Triangle QRT is a 45-45-90 triangle, which means it has the relationship x - x - x sqrt(2).
If RT is 4, then RQ must also be 4.
Answer: x = 4
Hope this helps!
Answer:
3 inches you are right
Step-by-step explanation:
Alright, lets get started.
We could use sine law to find the remaining angle.


Plugging the value of sin 64


Cross multiplying
sin S = 0.8189
Taking inverse on both side

S = 55° : Answer
Hope it will help :)