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3 years ago

Solve question 18 in the photo please ☺

Mathematics

1 answer:

Vadim26 [7]3 years ago

4 0

1) l₁= 1150 É with 25%
l₂=x With 20 %
So then make a proportion such as 1150/25 = x/20
criss cross multiply and you get x= 920.

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Which of the following is one of the special product formulas?

polet [3.4K]

Answer:

c .Perfect square trinomials

d.Difference of perfect squares

Step-by-step explanation:

We have to find the special product formulas.

a.Perfect square monomials

It is of the form $x^2$

It is not a special product formulas.

b.Difference of terms

It is of the form

$x-y$

It is not a special product formulas.

c.Perfect square trinomials

It is of the form

$(x+y)^2=x^2+y^2+2xy$

It is a special product formulas.

d.Difference of perfect squares

It is of the form

$x^2-y^2$

$(x+y)(x-y)$

Therefore, it is a special product formulas.

7 0

3 years ago

Read 2 more answers

Help<br><br><br> I really need help pls

Helga [31]

Answer

Mandisa uses more balloon per animal.

Amira and Mandisa made the same amount of balloon animals.

Explanation

Mandisa uses 5 balloons per animal.

You can find this out by putting the difference between two of the y values (output, dependent variable, in this case balloons) over the difference between two of the x values (input, independent variable, in this case animals). Let's take 225 and 125 from the y value and 20 and 40 from the x value. Mandisa uses 225-125=100 balloons per 40-20=20 animals. Mandisa uses 5 balloons per animal. 5 is more than 4 (how many balloons Amira uses for each animal), so Mandisa uses more balloons per animal.

Amira and Mandisa made the same amount of balloon animals.

Now you can divide the number of balloons they had at the beginning by the number of balloons per animal to find out how many animals each person made. Amira started with 260 balloons and used 4 balloons for each animal. Amira made 260/4=65 animals.

If Mandisa used 100 balloons to make 20 animals, she would have had 225+100=325 balloons at the beginning. Mandisa made 325/5=65 animals.

5 0

2 years ago

Thirteen people on a softball team show up for a game. a)How many ways are there to choose 10 players to take the field? b)How m

marishachu [46]

Answer:

a) 286

b) 1,037,836,800

c) 285

Step-by-step explanation:

a) Since order is not important, the total possible number of ways to choose 10 players out of 13 is the following combination:

$C(13,10)=\frac{13!}{(13-10)!10! } \\C(13,10)=\frac{13*12*11*10!}{(3*2*1)10! }\\C(13,10) = 286$

b) The total number of possibilities to assign positions by the selecting 10 players is the permutation of 13 players for 10 positions:

$P(13,10) = \frac{13!}{(13-10)!}\\P(13,10) = 13*12*11*10*9*8*7*6*5*4\\P(13,10) =1,037,836,800$

c) The number of ways to pick 10 players including at least one woman is equal to the total number of ways to pick 10 players (found in item a) minus the the number of ways to pick 10 players without picking a single woman.

Since there 10 male players for 10 positions, there is only one possible way to pick a team without women, therefore:

$P=286-1 =285$