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Archy [21]
2 years ago
6

If the sin of angle x is 4/5 and the triangle was dilated to be two times big as the original, what would be the value of the di

me of x for the dilated triangle?
Mathematics
1 answer:
Anon25 [30]2 years ago
7 0

Given :

Sin x = 4/5

Using the rule of SOH CAH TOA,

we know that,

Sin x = opposite/Hypotenuse

So,

When the triangle is dilated, the opposite side will be dilated to 8 and the Hypotenuse will be dilated to to 10.

which means 4/5 will become 8/10

and hence,

8/10 after simplifying will be 4/5.Thus there is no change.


Hope this helped!


Brainliest is very much appreciated.

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Answer:

1) \frac{dy}{dt}=2.5-\frac{3y}{2t+100}

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3) 98.23lbs

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Step-by-step explanation:

1) Let y represent the amount of salt in the tank at time t, where t is given in minutes.

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The rate of liquid leaving is is 3gal\min, so rate out is =\frac{3y(t)}{2t+100}

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\frac{dy}{dt}=2.5-\frac{3y}{2t+100}

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\frac{dy}{dt}+\frac{3}{2t+100}y=2.5

We multiply through by the integrating factor: e^{\int \frac{3}{2t+100}dt }=e^{\frac{3}{2} \int \frac{1}{t+50}dt }=(50+t)^{\frac{3}{2} }

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(50+t)^{\frac{3}{2} }\frac{dy}{dt}+(50+t)^{\frac{3}{2} }\cdot \frac{3}{2t+100}y=2.5(50+t)^{\frac{3}{2} }

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((50+t)^{\frac{3}{2} }y)'=2.5(50+t)^{\frac{3}{2} }

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