Answer:
The roots of the polynomial are;
3 + 2i
and 3-2i
Step-by-step explanation:
Here, we want to solve the given polynomial using the completing the square method
We start by dividing through by 8
This will give;
x^2 - 6x = -13
To complete the square, we simply divide the coefficient of x by 2 and square it
We have this as -6/2 = -3
square it;; = (-3)^2 = 9
Add it to both sides
x^2 - 6x + 9 = -13 + 9
x^2 - 6x + 9 = -4
(x-3)^2 = -4
Find the square root of both sides
x-3 = ±2i
x = 3 + 2i
or x = 3-2i
Answer:
Step-by-step explanation:
f(x) = 1/4 x²+bx+10
the derivate is : f'(x) = 1/2 x +b
you have : f'(6)=0
1/2 (6)+b=0
3+b =0
b = -3
so f(x) = 1/4 x²-3x+10.......f(6) =1/4(6)² -3(6)+10 =9-18+10 =1
f(x) = 1/4(x-6)²+1... the vertex form
Simplify the expression
-10
Hope this helps! :)