Answer:
y = |x| + 1
Step-by-step explanation:
1 can be anything greater than 0
Answer:
(a) 
The expected number in the sample that treats hazardous waste on-site is 0.383.
(b) 
There is a 0.000169 probability that 4 of the 10 selected facilities treat hazardous waste on-site.
Step-by-step explanation:
Professional Geographer (Feb. 2000) reported the hazardous waste generation and disposal characteristics of 209 facilities.
N = 209
Only eight of these facilities treated hazardous waste on-site.
r = 8
a. In a random sample of 10 of the 209 facilities, what is the expected number in the sample that treats hazardous waste on-site?
n = 10
The expected number in the sample that treats hazardous waste on-site is given by




Therefore, the expected number in the sample that treats hazardous waste on-site is 0.383.
b. Find the probability that 4 of the 10 selected facilities treat hazardous waste on-site
The probability is given by
For the given case, we have
N = 209
n = 10
r = 8
x = 4




Therefore, there is a 0.000169 probability that 4 of the 10 selected facilities treat hazardous waste on-site.
Answer:
<h2>3 + 4(n - 1)</h2>
Step-by-step explanation:
let r be the common differenc of the sequence
Term 12 - Term 7 = (12 - 7)r
then
47 - 27 = 5r
then
20 = 5r
then
r = 4
term 7 = term 1 + (7 - 1)r
then
27 = term 1 + 6r = term 1 + 24
then
Term1 = 27 - 24 = 3
<em><u>therefore </u></em>
the standard explicit formula of the sequence is :
term 1 + (n - 1)r = 3 + 4(n - 1)