River C : 200 + x
River D: x
200 + x + x = 5,540
combine like terms
200 + 2x = 5,540
subtract 200 from both sides
2x = 5,340
divide both sides by 2 to isolate the variable
x = 2, 670
River C: 200 + x = 200 + 2,670 = 2,870
River D: x = 2,670
2,870 + 2,670 = 5,540
Answer:
I believe it would be B.
Step-by-step explanation:
Range: area of variation with real numbers
Also, seeing the quadrant it is in means there are negative numbers. This takes out the possibility of option A.
Answer:
<h2>$6049.63</h2>
Step-by-step explanation:
the objective is to maximize profit
let x be corn and y be oat
let us begging by formulating the linear program for the problem
The objective function is
111x+47y=P
The constraints are
1. capital
36x+18y=2100------------1
2. labor
6x(8)+2y(8)=2400
48x+16y=2400-------------2
solving 1 and 2 we apply substitution method
36x+18y=2100------1
36x=2100-18y
x=(2100-18y)/36
put x=(2100-18y)/36 in 2 we have
48(2100-18y)/36+16y=2400
(100800-864y)/36+16y=2400
2800-24y+16y=2400
-8y=2400-2800
-8y=-400
8y=400
y=400/8
y=50
to find x put y=50 in 36x+18y=2100------------1
36x+18(50)=2100------------1
36x+900=2100
36x=2100-900
36x=1200
x=1200/36
x=33.33
profit is
111x+47y=P
111(33.33)+47(50)=P
3699.63+2350=P
P=6049.63
$6049.63
the planning comnination is to work on
33.33 acre of corn and 50 acre of oat
Answer:
The answer is number 1 because if you put it into a calculator correctly you'll get 10
Answer is the ratio 3:5
Explanation:
To write the pants to shirt ratio, we write the numbers 12 and 20 in that order (since they correspond to the counts of each clothing item). Separate them with a colon to get 12:20
The last step is to divide both parts by the GCF 4
12/4 = 3
20/4 = 5
The ratio 12:20 fully reduces to 3:5
For every 3 pairs of pants, you have 5 shirts.
