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Troyanec [42]
3 years ago
9

Ony is 12 of a mile ahead of laura on a jogging path. if tony is running at 5 miles per hour, and laura is running at 7 miles pe

r hour, how long will it take laura to catch up with tony?
Mathematics
1 answer:
xeze [42]3 years ago
8 0

Laura will take \frac{1}{4} hour or 15 minutes to catch up with Tony.

<u><em>Explanation</em></u>

Distance between Tony and Laura is \frac{1}{2} miles and the difference of their speeds = (7 - 5 ) mph = 2 mph

For catching up with Tony, Laura needs to travel that \frac{1}{2} miles with the speed of 2 mph

As, Distance = speed × time

So,  \frac{1}{2} = 2 × t

⇒ t = \frac{\frac{1}{2}}{2} = \frac{1}{4} hour = \frac{1}{4} × 60 minutes = 15 minutes

That means, Laura will take \frac{1}{4} hour or 15 minutes to catch up with Tony.

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The sum of 4 consecutive integers is 198. What is the fourth number in this sequence.
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Let x, x+1,x+2, x +3 are the <span>numbers
so
</span>x + x +1 + x +2 +x +3 = 198
4x + 6 = 198
4x =198-6
4x = 192
 x = 192/4
 x = 48
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 x + 2 = 48 + 2 = 50
 x + 3 = 48 + 3 = 51

proof
48 + 49 + 50 + 51 = 198

so the numbers are 48, 49, 50, 51

fourth number in this sequence is 51
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