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egoroff_w [7]
3 years ago
15

I need help answering this or at least help understanding how to do y=mx+b

Mathematics
1 answer:
Afina-wow [57]3 years ago
4 0

Answer:sle

Bruh moment

Step-by-step explanation:

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Evaluate the discriminant of the equation. Tell how many solutions each equation has and whether the solutions are real or imagi
cupoosta [38]

Answer:

D=-4<0, the equation has no real solutions, it has two imaginary solutions.

Step-by-step explanation:

The quadratic equation x^2 +4x+5=0 has coefficients

a=1,

b=4,

c=5.

The discriminant D is the expression

D=b^2-4ac.

Hence,

D=4^2-4\cdot 1\cdot 5=16-20=-4

Since the discriminant is negative, the equation has no real solutions, it has two imaginary solutions.

4 0
3 years ago
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Find the amount of each ordinary annuity. interest is compounded annually.
Svetlanka [38]
R=$350, I=0.05, n=15
A = 350 (1+0.05)^15 = 350(1.05)^15 = 350 (2.0789)=727.62 <- Answer
6 0
3 years ago
HELP ASAP IM IN A TIMED TEST 8TH GRADE MATH ​
sattari [20]

Answer:

C

Step-by-step explanation:

Convert them all to the form y = mx + c

1)

4x + 3y = 15

3y = -4x + 15

y = -4/3 x + 5

2)

3x - 4y = -8

-4y = -3x - 8

4y = 3x + 8

y = 3/4x + 2

3)

y + 1 = 4/3(x - 6)

y + 1 = 4/3x - 8

y = 4/3x - 9

4)

y = 3/4x - 5

8 0
3 years ago
AE and DF are parallel. If √ABG = 11x and m_HCF = 10x + 9, what is m√ABG? 102° 99° 81° 9° ​
katrin [286]

Answer:

81

Step-by-step explanation:

6 0
3 years ago
Lee watches TV for 2 hours per day. During that time, the TV consumes 250 watts per hour. Electricity costs (10 cents)/(1 kilowa
vladimir1956 [14]

Answer:

$1.5

Step-by-step explanation:

Lets us first calculate energy consumed by TV in 30 days.

Energy consumed by TV in one hour : 250 watts.

TV operated 2 hours a day

so energy consumer by TV in a day = 250 * 2 watts = 500 watts hour

Energy consumed by TV in 30 day = energy consumer by TV in a day * 30

         = 500*30 watts = 15,000 watt-hour

Convert total energy consumed in kilo watt hour  

we know that one kilowatt hour = 1000 watt-hour

Thus, 15,000 watt-hour = 15,000/1000 kilowatt-hour = 15 kilowatt-hour

________________________________

cost of electricity = 10 cents per   kilowatt-hour

cost of electricity for 15 kilowatt-hour = 15* cost of electricity for one  kilowatt-hour( which is 10 cents)

=>15*10 = 150 cents

As $1 = 100 cents

hence 150 cents = $150/100 = $1.5 .

Thus, it cost $1.5 to to operate for a month of 30 days.

6 0
3 years ago
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