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Nitella [24]
3 years ago
15

4x-y=2 2x+9y=-12 unsure how to solve

Mathematics
2 answers:
Anna11 [10]3 years ago
8 0
Simple, use the process of elimination to figure this out:

4x-y=2
2x+9y=-12

Convert these, to be able to find either x or y.

2(4x-y=2)   8x-2y=4   multiply by 2.
then
4(2x+9y=-12)  8x+36y=-48

Which makes them

8x-2y=4
-
8x+36y=-48

-38y=52

This simplified makes it y= -26/19.

Then plug y back into the original equation

4x-y=2

4x-(-26/19)=2

Making it x= 3/19.

Thus your Point of Intersection is at (3/19, -26/19)
sammy [17]3 years ago
3 0
4x-y=2 \\ 2x+9y=-12 \\ \\ ---- \\ \\ 4x - y = 2 \\ \\ 4x - y + 4 = 2 + y \\ \\ 4x = 2 + y \\ \\  \frac{4x}{4} =  \frac{2+y}{4} \\ \\ x =  \frac{2+y}{4} \\ \\ 2 \frac{2+y}{4} + 9y = -12 \\ \\ 9y +  \frac{y+2}{2} = -12 \\ \\ 2 \times 9y + 2 \frac{y+2}{2} = -2 \times 12 \\ \\ 19y + 2 = -24 \\ \\ 19y + 2 - 2 = -24 - 2 \\ \\ 19y = -26 \\ \\  \frac{19y}{19} =  \frac{-26}{19} \\ \\ y = - \frac{26}{19} \\ \\

-----

\\ \\ x =  \frac{2+y}{4} \\ \\ y = - \frac{26}{19} \\ \\ x =  \frac{2- \frac{26}{19} }{4} \\ \\ x =  \frac{3}{19} \\ \\

-----

The final result is: x = 3/19 and y = -26/19.
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For the graph, what is a reasonable constraint so that the function is at least 300?
blsea [12.9K]

Answer:

C) 0 ≤ x ≤ 25

Step-by-step explanation:

We are supposed to find a reasonable constraint so that the function is at least 300 i.e. the value of x at which f(x) is greater or equal to 300

A)x ≥ 0

Refer the graph

At x = 0

f(x)=300

On increasing the value of x , f(x) increases but at x = 12 it starts decreasing

So, x ≥ 0 can also have f(x)<300

So, Option A is wrong

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At x = -5

f(x) = 100

So, Option B is wrong since we require f(x) is greater or equal to 300

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D)All real numbers

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2x+8y = 6<br> 15x + 20y = 15
Likurg_2 [28]

Answer:

The solution is (0, 3/4)

Step-by-step explanation:

Please copy and share the instructions.  Here they are:  Solve the following system of linear equations.

Both of the equations can be reduced (simplified):

2x+8y = 6            =>  x + 4y = 3

15x + 20y = 15     => 3x + 4y = 3

Let's use the elimination by addition and subtraction method.  Multiply the first equation by -1, obtaining

                                 -x - 4y = -3

Add the second       3x + 4y = 3

equation to the

first.

We get:                       2x = 0.

Thus, x = 0.  Substituting 0 for x in the 1st original equation yields:

2(0) + 8y = 6.  Then y = 6/8, or y = 3/4.

The solution is (0, 3/4).

4 0
3 years ago
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