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Nitella [24]
3 years ago
15

4x-y=2 2x+9y=-12 unsure how to solve

Mathematics
2 answers:
Anna11 [10]3 years ago
8 0
Simple, use the process of elimination to figure this out:

4x-y=2
2x+9y=-12

Convert these, to be able to find either x or y.

2(4x-y=2)   8x-2y=4   multiply by 2.
then
4(2x+9y=-12)  8x+36y=-48

Which makes them

8x-2y=4
-
8x+36y=-48

-38y=52

This simplified makes it y= -26/19.

Then plug y back into the original equation

4x-y=2

4x-(-26/19)=2

Making it x= 3/19.

Thus your Point of Intersection is at (3/19, -26/19)
sammy [17]3 years ago
3 0
4x-y=2 \\ 2x+9y=-12 \\ \\ ---- \\ \\ 4x - y = 2 \\ \\ 4x - y + 4 = 2 + y \\ \\ 4x = 2 + y \\ \\  \frac{4x}{4} =  \frac{2+y}{4} \\ \\ x =  \frac{2+y}{4} \\ \\ 2 \frac{2+y}{4} + 9y = -12 \\ \\ 9y +  \frac{y+2}{2} = -12 \\ \\ 2 \times 9y + 2 \frac{y+2}{2} = -2 \times 12 \\ \\ 19y + 2 = -24 \\ \\ 19y + 2 - 2 = -24 - 2 \\ \\ 19y = -26 \\ \\  \frac{19y}{19} =  \frac{-26}{19} \\ \\ y = - \frac{26}{19} \\ \\

-----

\\ \\ x =  \frac{2+y}{4} \\ \\ y = - \frac{26}{19} \\ \\ x =  \frac{2- \frac{26}{19} }{4} \\ \\ x =  \frac{3}{19} \\ \\

-----

The final result is: x = 3/19 and y = -26/19.
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The area of a rectangle is 2x*2-13x+12 and another area is 6x^2-13x+21, what is the combined area of both rectangles?
saul85 [17]

Answer:

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Step-by-step explanation:

Add the expressions.

2x^2 - 13x + 12 + 6x^2 - 13x + 21 =

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GuDViN [60]
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<h3>What is the triangle?</h3>

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The sides of the triangle are 4.7 m, 1.6 m, and 2.9 m.

The condition will be

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More about the triangle link is given below.

brainly.com/question/25813512

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