Answer:
No, The 8 in the ones place of the decimal and the 8 in the thousands. Decimals go by variables of 10 if that makes sense
so hopping from the 8 in the ones place it would go 10, 100,1000.
Therefore the statement is false because the value between the eitghts is not 100 its 1000
Answer:
x = 125°
Step-by-step explanation:
180° - 55° = 125°
125°
If my answer is incorrect, pls correct me!
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-Chetan K
<h2>
Answer with explanation:</h2>
Consider a sampling distribution with p equals 0.12 and samples of size n each.
Then, formula for mean = p
Formula for standard deviation= 
(a) For a random sample of size n equals 5000.
Mean = 0.12
Standard deviation= 

(b) For a random sample of size n equals 1000.
Mean = 0.12
Standard deviation= 

(c) For a random sample of size n equals 500.
Mean = 0.12
Standard deviation= 

Answer:
96.38
Step-by-step explanation:
how to find 79% of 122
122/100=1.22
79*1.22=96.38
Answer:
Hi! The formula for surface area is:
area = 2lw + 2lh + 2hw
(l = length, w = width, h = height.)
<em>Hope this helps! :)</em>