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Mumz [18]
3 years ago
14

Find the distance between the points given. (2, 5) and (6, 8)

Mathematics
1 answer:
inna [77]3 years ago
6 0
(2,5) , (6,8)

Distance formula : 

d = √(x₂-x₁)² + (y₂-y₁)²

Simply plug in the values.

d = √(6 - 2)² + (8 - 5)²

Simplify.

d = √(4)² + (3)²

Simplify.

d = √16 + 9

Simplify.

d = √25

So, the distance is 5

~Hope I helped!~
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The midpoint of AB is at (3,7) and A is at (0,-5). Where is B located?
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\bf \textit{middle point of 2 points }\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
&({{ \square }}\quad ,&{{ \square }})\quad 
%  (c,d)
&({{ \square }}\quad ,&{{ \square }})
\end{array}\qquad
%   coordinates of midpoint 
\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)\qquad thus
\\
----------------------------\\\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
A&({{ 0}}\quad ,&{{ -5}})\quad 
%  (c,d)
B&({{ \square }}\quad ,&{{ \square }})
\end{array}\qquad
%   coordinates of midpoint 
(3,7)\impliedby midpoint\qquad thus
\\ \quad \\
\left(\cfrac{{{ x_2 }} + {{ 0}}}{2}=3\quad ,\quad \cfrac{{{ y_2 }} + {{( -5)}}}{2}=7 \right)\to 
\begin{cases}
\cfrac{{{ x_2 }} + {{ 0}}}{2}=3
\\ \quad \\
\cfrac{{{ y_2 }} + {{ -5}}}{2}=7
\end{cases}
\\ \quad \\
solve\ for\ x_2\ and\ y_2
3 0
3 years ago
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