3 years ago

Twice the smallest of three consecutive odd integers is nine more than the largest. find the integers.

1 answer:

7 0

let x x +2 x+4 three consecutive odd integers

2x =9+ x+4 Twice the smallest is nine more than the largest
2x - x= 13

x= 13 the first
the second integer 15 the third 17

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IRISSAK [1]

The wording of this question is a bit confusing... You can't write a sequence in sigma notation, but rather a series or sum. I think the question is asking you to write the sum of the sequence,

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To do this, notice that the denominator in each term is a power of 2, starting with $2^1=2$ and ending with $2^6=64$ . So in sigma notation, this series is