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Degger [83]
3 years ago
10

Twice the smallest of three consecutive odd integers is nine more than the largest. find the integers.

Mathematics
1 answer:
polet [3.4K]3 years ago
7 0
 let   x        x +2       x+4     three consecutive odd <span>integers


2x =9+ x+4   </span>Twice the smallest<span> is nine more than the largest 
 2x - x= 13

x= 13  the first 
the second integer 15   the third  17 </span>
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10 POINTS!!! FULL ANSWER IN STEP BY STEP FORMAT!!
In-s [12.5K]
Remark
This question likely should be done before the other one. What you are trying to do is give C a value. So you need to remember that C is always part of an indefinite integral.

y = \int (cos(x) + sin(x) ) \, dx = \int{cos(x) \,dx + \int sin(x) \,dx
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y = sin(x) - cos(x) - 1  <<<<< Answer

Problem Two
Remember that y =  \int\ { \frac{1}{x} } \, dx = ln(|x|) + C
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y(-e^3) = ln(|-e^3|) + C = 0
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3 years ago
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Answer:

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