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Sedbober [7]
3 years ago
5

Lines need to be painted on the field at a football stadium. The painter estimated that one can of paint would last 11 yards. Ho

w many cans of paint will be needed to paint the length of the 100-yard field?
I've been stuck on this question for two days :,) the answers are A.8 B.10 C.12 D.14





Can someone please tell me the answer?
Mathematics
1 answer:
zlopas [31]3 years ago
8 0

Answer:  

area = pi*24^2/4 = 452 yd^2

so that means you will need 452/59 = 7.6 (or 8) gallons

You might be interested in
What is the value of (-7+3i)+(2-6i)? A)-9+9i B)-5+9i C) -9-3i D) -5-3i
Delicious77 [7]

Answer:

D

Step-by-step explanation:

Add real numbers and add imaginary numbers

(-7 + 3i)+(2 - 6i) = -7 + 2 + 3i - 6i

                        =  - 5 - 3i

4 0
3 years ago
Read 2 more answers
Which increase faster, f(x)=5x or g(x)=5^x
hichkok12 [17]

g(x) = 5^x is your answer

Plug in increasing numbers for x to get the output.

For example: when x = 1

f(1) = 5(1) = 5

g(1) = 5^(1) = 5

when x = 2

f(2)= 5(2) = 10

g(2) = 5^(2) = 25

when x = 3

f(3) = 5(3) = 15

g(3) = 5^(3) = 125

~

From the example above, we see that g(x) = 5^x is your answer

~

5 0
4 years ago
A lumber company is making doors that are 2058.0 millimeters tall. If the doors are too long they must be trimmed, and if the do
USPshnik [31]

Answer:

No, we don't have sufficient evidence to support the claim that the doors are either too long or too short.

Step-by-step explanation:

We are given that a lumber company is making doors that are 2058.0 millimeters tall. If the doors are too long they must be trimmed, and if the doors are too short they cannot be used.

A sample of 11 is made, and it is found that they have a mean of 2043.0 millimeters with a standard deviation of 25.0.

Let \mu = <u><em>population mean length of doors</em></u>.

So, Null Hypothesis, H_0 : \mu = 2058.0 millimeters      {means that the mean length of doors is 2058.0 millimeters}

Alternate Hypothesis, H_A : \mu\neq 2058.0 millimeters     {means that the doors are either too long or too short}

The test statistics that will be used here is <u>One-sample t-test statistics</u> because we know about the population standard deviation;

                               T.S.  =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean = 2043.0 millimeters

             s = sample standard deviation = 25.0 millimeters

             n = sample of doors = 11

So, <u>the test statistics</u> =  \frac{2043.0-2058.0}{\frac{25.0}{\sqrt{11} } }

                                     =  -1.989  

The value of t-test statistics is -1.989.

Now, at a 5% level of significance, the t table gives a critical value between -2.228 and 2.228 at 10 degrees of freedom for the two-tailed test.

Since the value of our test statistics lies within the range of critical values of t, so <u><em>we have insufficient evidence to reject our null hypothesis</em></u> as it will not fall in the rejection region.

Therefore, we conclude that the mean length of doors is 2058.0 millimeters.

7 0
3 years ago
16.089 round to nearest 10
zepelin [54]
20 because 16 is greater than 15 and we round the number up.
8 0
3 years ago
What is the solution of log2 (3x-7) =3
Valentin [98]

Answer:

x = 5

Step-by-step explanation:

because the log is base 2 you can remove the log by raing 2 to the power of each side:

2^{log2 (3x-7)} = 2^{3}

the 2 and log2 cancel leaving:

3x-7 = 2^{3}

this means we can now solve through simple algebra:

3x-7 = 8\\3x = 8 + 7\\3x = 15\\3x/3 =15/3\\x = 5

7 0
3 years ago
Read 2 more answers
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