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valina [46]
2 years ago
10

Please quickly! Out of 5,500 people who attended the football game, fifty-six percent were rooting for the home team. How many p

eople rooted for the home team?
Mathematics
1 answer:
tigry1 [53]2 years ago
5 0
3,080 people rooted for the hometeam.
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How do u make 25 m to *what* cm?
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Answer:

2500 cm

Step-by-step explanation:

1 meter = 100 cm

25m x 100 = 2500 cm

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What's the nearest tenth of 1.91
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1.91 to the nearest tenth is 1.9
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Is the function increasing or decreasing over the interval [-3, -1)? Explain.
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Answer:I actually don’t know

Step-by-step explanation:

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3 years ago
Before the pandemic cancelled sports, a baseball team played home games in a stadium that holds up to 50,000 spectators. When ti
spayn [35]

Answer:

(a)D(x)=-2,500x+60,000

(b)R(x)=60,000x-2500x^2

(c) x=12

(d)Optimal ticket price: $12

Maximum Revenue:$360,000

Step-by-step explanation:

The stadium holds up to 50,000 spectators.

When ticket prices were set at $12, the average attendance was 30,000.

When the ticket prices were on sale for $10, the average attendance was 35,000.

(a)The number of people that will buy tickets when they are priced at x dollars per ticket = D(x)

Since D(x) is a linear function of the form y=mx+b, we first find the slope using the points (12,30000) and (10,35000).

\text{Slope, m}=\dfrac{30000-35000}{12-10}=-2500

Therefore, we have:

y=-2500x+b

At point (12,30000)

30000=-2500(12)+b\\b=30000+30000\\b=60000

Therefore:

D(x)=-2,500x+60,000

(b)Revenue

R(x)=x \cdot D(x) \implies R(x)=x(-2,500x+60,000)\\\\R(x)=60,000x-2500x^2

(c)To find the critical values for R(x), we take the derivative and solve by setting it equal to zero.

R(x)=60,000x-2500x^2\\R'(x)=60,000-5,000x\\60,000-5,000x=0\\60,000=5,000x\\x=12

The critical value of R(x) is x=12.

(d)If the possible range of ticket prices (in dollars) is given by the interval [1,24]

Using the closed interval method, we evaluate R(x) at x=1, 12 and 24.

R(x)=60,000x-2500x^2\\R(1)=60,000(1)-2500(1)^2=\$57,500\\R(12)=60,000(12)-2500(12)^2=\$360,000\\R(24)=60,000(24)-2500(24)^2=\$0

Therefore:

  • Optimal ticket price:$12
  • Maximum Revenue:$360,000

3 0
3 years ago
Point A of rectangle ABCD is located at coordinates (3,7). If rectangle ABCD is translated down 7 and left 5, what are the new c
uranmaximum [27]

Answer:

The new co-ordinates are A¹ ( -2 , 0)

Step-by-step explanation:

<u><em>Step(i):</em></u>-

Point A of rectangle ABCD is located at coordinates (3,7).

<u><em>Type of transformation </em></u><em>                               </em><u><em> change of co-ordinate point</em></u>

<em>Vertical translation up 'd' units                   (x, y)→ (x, y +d)</em>

<em>Vertical translation down 'd' units              (x, y)→ (x, y -d)</em>

<em>Horizontal translation left 'C' units              (x, y)→ (x - c , y) </em>

<em>Horizontal translation right 'C' units             (x, y)→ (x + c , y) </em>

<u><em>Step(ii</em></u><em>):-</em>

<em>Given rectangle ABCD is translated down 7 and left 5</em>

<em>Given Point A(3 ,7) </em>

Vertical translation down '7' units  t

The new co-ordinate A¹ ( 3 , 7-7)→ A¹( 3, 0) and Horizontal translation left ''5' units

Now the new co-ordinates are A¹ ( 3-5 , 7-7)

<u><em>Final answer:-</em></u>

The new co-ordinates are A¹ ( -2 , 0)

7 0
3 years ago
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