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3 years ago

What is the perimeter of the figure to the nearest tenth of a millimeter?

Mathematics

1 answer:

trapecia [35]3 years ago

6 0

C because first you would find the circumference of the circle which is pi times diameter, which is 18.84 but since it is a semi-circle you would divide by 2 which is 9.42. Then you do 3+3=6 + the length which is 6 so you get 12. 12+9.42=21.42 and if you round that to the nearest tenth it is 21.42.

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a rectangle is 5 inches long and 2x inches wide. The value of the perimeter is 22 inches what is the value of x?

Alekssandra [29.7K]

Answer: x =3

Step-by-step explanation:

2× 3 = 6

length= 5 inches

width= 2×3= 6 inches

2(l+w) = 2(5+6)

2(11)

2×11= 22

hope this helps:-)

4 0

2 years ago

. Consumer Awareness In 1986, the average cost of a new midsize four-door sedan was $9000. In 1991, the average cost was $12,000

eduard

Answer-

$\boxed{\boxed{y=9000(1.0592)^x}}$

And cost of a car in the year 2000 will be $20134.18

Solution-

Let's assume,

x = number of years after 1986

y = average cost of sedan in dollar

The exponential model that will model the scenario will be in the form of,

$y=ab^x$

where a and b are constants

As given that, in 1986 average cost of sedan was $9000 and in 1991 average cost of sedan was $12000

So, the points (0, 9000) and (5, 12000) will satisfy or lie on the exponential curve.

Putting (0, 9000) in the equation,

$\Rightarrow 9000=ab^0$

$\Rightarrow a\times 1=9000$

$\Rightarrow a=9000$

Now, the equation becomes $y=9000b^x$

Putting (5, 12000) in this equation,

$\Rightarrow 12000=9000b^5$

$\Rightarrow b^5=\dfrac{12000}{9000}$

$\Rightarrow b=\sqrt[5]{\dfrac{4}{3}}$

$\Rightarrow b=1.0592$

Putting the values,

$y=9000(1.0592)^x$

As we have to calculate the cost of sedan in 2000, so putting x=14(as 2000-1986=14),

$y=9000(1.0592)^{14}=20134.18$

Therefore, cost of a car in the year 2000 will be $20134.18

8 0

2 years ago

What is each percent of change?

Evgen [1.6K]

Answer:

there is a 50% increase of change from 200 to 300. What do you mean by total cost or sale price?

Step-by-step explanation:

7 0

2 years ago

Multiply: 4x * root(3, 4x ^ 2) * (2 * root(3, 32x ^ 2) - x * root(3, 2x))

Salsk061 [2.6K]

Answer:

$32 {x}^{2} \sqrt[3]{ 2x } -8{x}^{3}$

Step-by-step explanation:

We want to

$4x \sqrt[3]{4 {x}^{2} } (2 \sqrt[3]{32 {x}^{2} } - x \sqrt[3]{2x} )$

We expand to obtain:

$4x \sqrt[3]{4 {x}^{2} } \times 2 \sqrt[3]{32 {x}^{2} } -4x \sqrt[3]{4 {x}^{2} } \times x \sqrt[3]{2x} )$

We now simplify

$8x \sqrt[3]{4 {x}^{2} \times 32 {x}^{2} } -4 {x}^{2} \sqrt[3]{4 {x}^{2} \times 2x}$

We multiply the radicand

$8x \sqrt[3]{64 \times {x}^{3} \times 2x } -4 {x}^{2} \sqrt[3]{8 {x}^{3}}$

$8x \sqrt[3]{ {(4x)}^{3} \times 2x } -4 {x}^{2} \sqrt[3]{{(2x)}^{3}}$

We take cube root to get:

$8x \times 4x\sqrt[3]{ 2x } -4 {x}^{2} \times 2x$

We multiply out to get:

$32 {x}^{2} \sqrt[3]{ 2x } -8{x}^{3}$

6 0

3 years ago

Read 2 more answers

If f(x) = -x2 – 1, and

Marysya12 [62]

Answer:

g(f(x)) = -x^2 + 4

Step-by-step explanation:

What we simply have to do here is to put f(x) into g(x)

What this mean is that every x in g(x) will be represented by f(x)

Thus, we have it that

-x^2 - 1 + 5

= -x^2 + 4

6 0

2 years ago