A BOWL HAS SLIPS OF PAPER WITH A SINGLE NUMBER ON IT WITH NUMBERS FROM 2 TO 13. NO NUMBER IS REPEATED. WHAT ARE THE ODDS AGAINST
PICKING A PRIME NUMBER AT RANDOM?
2 answers:
Answer:
4/13 chance
Step-by-step explanation:
Because there the prime numbers between 2 and 13 are 5, 7, and 11 if you are not including 2 and 13.
you have a 58%(rounded) chance against picking a prime number at random
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Answer:
44-34= 10+89=99 marbles
Step-by-step explanation:
Answer: a = 3.5
Step-by-step explanation:
14=4a
divide both sides by 4
14/4 = 3.5
4a/4 =1a or a
so a= 3.5
That would be a total of 32
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