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lina2011 [118]
3 years ago
13

A BOWL HAS SLIPS OF PAPER WITH A SINGLE NUMBER ON IT WITH NUMBERS FROM 2 TO 13. NO NUMBER IS REPEATED. WHAT ARE THE ODDS AGAINST

PICKING A PRIME NUMBER AT RANDOM?
Mathematics
2 answers:
Marat540 [252]3 years ago
7 0

Answer:

4/13 chance

Step-by-step explanation:

Because there the prime numbers between 2 and 13 are 5, 7, and 11 if you are not including 2 and 13.

iren2701 [21]3 years ago
3 0

you have a 58%(rounded) chance against picking a prime number at random

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Step-by-step explanation:

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3 0
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PLZZZZ HELP ASAP PLZZZ
11111nata11111 [884]

Answer:

1. (5x - 2) + (2x - 2) + x = 180^{o}

2. m<J = 113^{o}

3. m<K = 44^{o}

4. m<L = 23^{o}

Step-by-step explanation:

Generally, the sum of angles in a triangle = 180^{o}.

So that;

m<J + m<K + m<L = 180^{o}

(5x - 2) + (2x - 2) + x = 180^{o}

5x + 2x + x -2 -2 = 180^{o}

8x - 4 = 180^{o}

8x = 180^{o} + 4

8x = 184

x = \frac{184}{8}

x = 23^{o}

Thus,

m<J = (5x - 2)

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m<K = (2x -2)

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m<L = x

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3 0
3 years ago
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6 x 8 = 48

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