9514 1404 393
Answer:
Step-by-step explanation:
The left section is defined at x = -5, but not at x = 0, so the interval for that definition is -5 ≤ x < 0. The function value on that interval is constant: 3.
The right section is defined a x = 5, but not at x = 0, so the interval for that definition is 0 < x ≤ 5. That section is a straight line with a slope of -1 and a y-intercept of 1. The function value on that interval can be written -x+1.
Then the piecewise definition is ...
f(x) = {3, for -5 ≤ x < 0; -x+1, for 0 < x ≤ 5}
Answer:
5
Step-by-step explanation:
1. in order to calculate all the required values, it needed to solve:
2. x≥5 means, that x∈[5;+∞), where beginnig is '5'.
Answer:
1. (a-c)
+ b
2. 9m + 2
3. 6a
4. (5a - 3b)
Step-by-step explanation:
1. since a and c share the same squareroot x, you can combine these together.
2. First add like terms together. 4m - m + 6m = 9m. Then 5 and -3 combined equals 2
3. First simplify the square roots. squareroot of 16 is 4. square root of 49 is 7. square root of 81 is 9. They are all multiplied by a in the expression. Thus 4a - 7a + 9a = 6a
4. First simplify the radicals, they are not perfect. square root of 125 is equivalent to sqrt(25 * 5), which sqrt of 25 is 5, but we keep the sqrt of 5. For sqrt of 45, it is the same as sqrt9 * sqrt5. sqrt of 9 is the same as 3 and we keep sqrt 5. Thus we get the below:
5a - 3b
We can combine the two like terms and get the final answer above.
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If f(1) =5-2(1)
F(2)=5-2(2)
Answer:
B.
Step-by-step explanation:
