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3 years ago

Which of the following could be used as a straightedge? Select all that apply.

Mathematics

2 answers:

evablogger [386]3 years ago

8 0

A and B, though B would be the best choice, because they all have an edge that is straight.

Vesnalui [34]3 years ago

6 0

Answer:

The answer is A , B

Step-by-step explanation:

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28 dimes to 32 dimes

arlik [135]

28:32. That is 28 to 30 dimes hoped I helped you

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3 years ago

ZOOM IN ON PICK

salantis [7]

Answer:

C. The difference of the medians is 4 times the interquartile range.

Step-by-step explanation:

The diagram show two box plots.

<u>Mahoney's box plot:</u>

Median $=33$

Interquartile range $=34-32=2$

<u>Martin's box plot:</u>

Median $=41$

Interquartile range $=42-40=2$

The interquartile ranges are the same.

The difference of the medians $=41-33=8$

Hence, the difference of the medians is 4 times the interquartile range.

6 0

3 years ago

You guysss pls help me

hichkok12 [17]

Answer:

option B) $\frac{1}{12}$

Step-by-step explanation:

According to the given conditions, the total number of outcomes are 24.

The probability that of drawing hearts card is

P= $\frac{(total number of hearts cases)}{(total number of cases)}$

total number of hearts cases= 6

thus P= $\frac{6}{24} = \frac{1}{4}$

now the probability of 4 or 6 is,

P= $\frac{(total number of 4 or 6 cases)}{(total number of cases)}$

thus P= $\frac{8}{24} = \frac{1}{3}$

thus, by multiplication law,

final probality is P= $(\frac{1}{4})(\frac{1}{3})$

P= $\frac{1}{12}$

5 0

3 years ago

Find the median, range, and interquartile range of both sets: Set 1: 65, 66, 77, 79, 81, 93, 104, 105 Set 2: 56, 1, 29, 72, 67,

nikitadnepr [17]

Answer:

the answer is c.

Step-by-step explanation:

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3 years ago

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Linda and her three sisters have a total of 37 dolls. Linda has twice as many dolls as Jessica. Rebecca has 3 times the number o

yulyashka [42]

I answered it in a table as seen above, place the amount in terms of X and then work out what X is equal to

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3 years ago