Answer:
3... 5,7....x,y....12
Step-by-step explanation:
Numbers of Terms: 3
Coefficients: 5 and 7
Variables: x and y
Constant: 12
Well, you can ask yourself what is half of eight and thats it. btw 5/8 is larger
i. 171
ii. 162
iii. 297
Solution,
n(U)= 630
n(I)= 333
n(T)= 168
i. Let n(I intersection T ) be X
<h3>ii.
n(only I)= n(I) - n(I intersection T)</h3><h3>
= 333 - 171</h3><h3>
= 162</h3>
<h3>
iii. n ( only T)= n( T) - n( I intersection T)</h3><h3>
= 468 - 171</h3><h3>
= 297</h3>
<h3>
Venn- diagram is shown in the attached picture.</h3>
Hope this helps...
Good luck on your assignment...
Set up a system of equations:
2l + 2w = 72
l = 2w
Solve the system using substitution:
2(2w) + 2w = 72
Solve for w:
4w + 2w = 72
—> 6w = 72
—> w = 12
Plug in the value for ‘w’ in the second equation:
l = 2(12)
—> l = 24
The width is 12.
The length is 24.
